1 files changed, 61 insertions, 0 deletions
diff --git a/929/CH2/EX2.10.b/Example2_10_b.sce b/929/CH2/EX2.10.b/Example2_10_b.sce
new file mode 100755
index 000000000..ca26d821e
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+++ b/929/CH2/EX2.10.b/Example2_10_b.sce
@@ -0,0 +1,61 @@
+//Example 2.10(b)
+
+clear;
+
+clc;
+
+Amin=1;
+
+Amax=10^3;
+
+AI=0.5;
+
+R1=100*10^3;//Tolerance (1%)
+
+R2=AI*R1;//Tolerance (1%)
+
+AImin=Amin/AI;
+
+AImax=Amax/AI;
+
+//AImin<=AI<=AImax
+//AImin=1+((2*R3)/(R4+R1)) -> 1+((2*R3)/(R4+R1))-Amin=0 -> (1-AImin)*R4+2*R3+(1-AImin)*R1=0...(i) and AImax=1+((2*R3)/(R4+0)) ->(1-AImax)*R4+2*R3=0....(ii)
+//Solving these two equations will give R3 and R4
+
+A=[2 (1-AImin);2 (1-AImax)];
+
+B=[(1-AImin)*R1;0];
+
+R=linsolve(A,B);
+
+R3=R(1,1);//Tolerance (1%)
+
+R4=R(2,1);//Tolerance (1%)
+
+p=0.01;
+
+e=4*p*R2;
+
+R5=100*10^3;
+
+R2red=R2-e-500;//to be on the safer side 0.5 kohms more is reduced 
+
+Rpot=2*(R2-R2red);//Potentiometer Resistance
+
+//Circuit is shown in Fig.2.21 in the book
+
+printf("Designed Instrumentation Amplifier with trimmed resistances :");
+
+printf("\nR1=%.2f kohms",R1*10^(-3));
+
+printf("\nR2=%.2f kohms",R2*10^(-3));
+
+printf("\nR3=%.f kohms",R3*10^(-3));
+
+printf("\nR4=%.f ohms",R4);
+
+printf("\nR5=%.f kohms",R5*10^(-3));
+
+printf("\nR6=%.2f kohms",R2red*10^(-3));
+
+printf("\nR7=%.2f kohms",Rpot*10^(-3));
+\ No newline at end of file