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diff --git a/926/CH2/EX2.2/Chapter2_Example2.sce b/926/CH2/EX2.2/Chapter2_Example2.sce new file mode 100644 index 000000000..12db85149 --- /dev/null +++ b/926/CH2/EX2.2/Chapter2_Example2.sce @@ -0,0 +1,20 @@ +//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504
+
+//Chapter-2, Illustration 2, Page 31
+//Title: Calculating mass from given volume at standard conditions
+//=============================================================================
+clear
+clc
+
+//INPUT
+v = 500; //Volume of gaseous propane in liters
+mw = 44.06; //Molecular weight of propane in g/g mole
+
+//CAlCULATION
+n = v/22.4; //To find the no of moles of propane in g mole
+m = n*mw; //To calculate the weight of propane in grams
+
+//OUTPUT
+mprintf('\n Weight of liquid propane formed after liquification = %3.0f grams',m);
+
+//==============================END OF PROGRAM=================================
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