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+clc;
+warning("off");
+printf("\n\n example9.3 - pg389");
+Nblades=4; // no. of blades
+d=9/12; //[ft] - diameter of the impeller
+dt=30/12; //[ft] - diameter of the tank
+Nbaffles=4; // no. of baffles
+h=30; // [inch] - height of unit
+mu=10; //[cP] - viscosity of fluid
+sg=1.1; // specific gravity of fluid
+s=300; //[rpm] - speed of agitator
+CbyT=0.3;
+V=(%pi*dt^3)/4; //volume of tank in ft^3
+V1=V*7.48; //[gal] - volume of tank in gallons
+mu=mu*(6.72*10^-4); //[lb/ft*sec]
+p=sg*62.4; //[lb/ft^3] - density of fluid
+N=s/60; //[rps] - impeller speed in revolutions per second
+Nre=((d^2)*N*p)/mu;
+disp(Nre,"Nre=");
+printf("\n\n Therefore the agitator operates in the turbulent region");
+Npo=1.62;
+gc=32.174;
+P=(Npo*(p*(N^3)*(d^5)))/(gc*550);
+Cf=63025;
+Tq=(P/s)*Cf;
+PbyV=P/V;
+PbyV1=P/V1;
+TqbyV=Tq/V;
+TqbyV1=Tq/V1;
+printf("\n\n The power per unit volume and the torque per unit volume is \n P/V=%f hp/ft^3=%f hp/gal\n Tq/V=%f in*lb/ft^3=%f in*lb/gal",PbyV,PbyV1,TqbyV,TqbyV1);
+
+