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diff --git a/914/CH7/EX7.3/ex7_3.sce b/914/CH7/EX7.3/ex7_3.sce
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+clc;
+warning("off");
+printf("\n\n example7.3 - pg274");
+// given
+// composition of fuel gas
+nH2=24;
+nN2=0.5;
+nCO=5.9;
+nH2S=1.5;
+nC2H4=0.1;
+nC2H6=1;
+nCH4=64;
+nCO2=3.0;
+// calculating the theoritical amount of O2 required
+nO2theoreq=12+2.95+2.25+0.30+3.50+128;
+// since fuel gas is burned with 40% excess O2,then O2 required is
+nO2req=1.4*nO2theoreq;
+nair=nO2req/0.21;  // as amount of O2 in air is 21%
+nN2air=nair*(0.79);  // as amount of N2 in air is 79%
+nN2=nN2+nN2air;
+nO2=nO2req-nO2theoreq;
+nH2O=24+0+0.2+3.0+128;
+nCO2formed=72.1;
+nCO2=nCO2+nCO2formed;
+nSO2=1.5;
+ntotal=nSO2+nCO2+nO2+nN2+nH2O;
+mpSO2=(nSO2/ntotal)*100;
+mpCO2=(nCO2/ntotal)*100;
+mpO2=(nO2/ntotal)*100;
+mpN2=(nN2/ntotal)*100;
+mpH2O=(nH2O/ntotal)*100;
+printf("\n\n gas                            N2                O2             H2O         CO2           SO2");
+printf("\n\n moles                       %f     %f      %f      %f    %f",nN2,nO2,nH2O,nCO2,nSO2);
+printf("\n\n mole percent                  %f     %f      %f      %f    %f",mpN2,mpO2,mpH2O,mpCO2,mpSO2);
+
+
+
+
+
+