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+clc;
+warning("off");
+printf("\n\n example13_6 - pg684");
+// given
+d=1*0.0254; //[m]
+Lr=d/2; //[m];
+Lz=(1.2/2)*(0.0254);
+x=Lz;
+r=Lr;
+k=0.481;
+h=20;
+mr=k/(h*Lr);
+mz=k/(h*Lz);
+nr=r/Lr;
+nz=x/Lz;
+t=1.2; //[sec]
+alpha=1.454*10^-4;
+Xr=(alpha*t)/(Lr^2);
+Xz=(alpha*t)/(Lz^2);
+// using the above value of m,n,X the value for Ycz and Ycr from fig 13.14 is
+Ycr=0.42;
+Ycz=0.75;
+Yc=Ycr*Ycz;
+T_infinity=400; //[K]
+To=295;
+Tc=T_infinity-(Yc*(T_infinity-To));
+printf("\n\n The temperature t the centre is \n Tc = %f K",Tc);
+
+