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+clc;
+warning("off");
+printf("\n\n example12.16 - pg624");
+// given
+d=24*10^-6; //[m] - diameter of wire
+T=415; //[K] - operating temperature of hot wire anemometer
+P=0.1; //[W] - power consumption
+L=250*d;
+Tair=385; //[K] - temperature of air in duct
+A=%pi*d*L;
+Tfilm=(T+Tair)/2;
+// properties of air at Tfilm
+p=0.8825; //[kg/m^3]
+mu=2.294*10^-5; //[kg/m*s]
+cpf=1013; //[J*kg/K]
+kf=0.03305; //[W/m*K]
+Npr=0.703;
+h=P/(A*(T-Tair));
+Nnu=(h*d)/kf;
+function y=func(x)
+ y=Nnu-0.3-((0.62*(x^(1/2))*(Npr^(1/3)))/((1+((0.4/Npr)^(2/3)))^(1/4)))*((1+((x/(2.82*(10^5)))^(5/8)))^(4/5));
+endfunction
+// on solving the above function for x by using some root solver technique like Newton raphson method , we get
+x=107.7;
+// or
+Nre=107.7;
+y=func(x);
+Um=(Nre*mu)/(d*p);
+printf("\n\n The velocity is \n Um = %f m/sec = %f ft/sec",Um,Um*3.28);