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+clc;
+warning("off");
+printf("\n\n example11.10 - pg544");
+// given
+Ui=325; //[W/m^2*K] - overall heat transfer coefficient
+Thi=120; //[degC] - inlet temperature of hydrocarbon
+Tho=65; //[degC] - outlet temperature of hydrocarbon
+Tci=15; //[degC] - inlet temperature of water
+Tco=50; //[degC] - outlet temperture of water
+cp=4184; //[J/kg*K] - heat capacity of water
+ch=4184*0.45; //[J/kg*K] - heat capacity of hydrocarbon
+wc=1.2; //[kg/sec] - mass flow rate of water
+wh=((wc*cp)*(Tco-Tci))/((ch)*(Thi-Tho));
+qtotal=wc*cp*(Tco-Tci);
+// (a) - parallel double pipe
+F=1;
+Thi=120; //[degC] - inlet temperature of hydrocarbon
+Tho=65; //[degC] - outlet temperature of hydrocarbon
+Tci=15; //[degC] - inlet temperature of water
+Tco=50; //[degC] - outlet temperture of water
+deltaT1=Thi-Tci;
+deltaT2=Tho-Tco;
+LMTD=(deltaT2-deltaT1)/(log(deltaT2/deltaT1));
+Ai=qtotal/((Ui*LMTD));
+printf("\n\n (a) parallel double pipe \n Ai = %f m^2",Ai);
+// (b) - counter flow
+F=1;
+Thi=120; //[degC] - inlet temperature of hydrocarbon
+Tho=65; //[degC] - outlet temperature of hydrocarbon
+Tco=15; //[degC] - inlet temperature of water
+Tci=50; //[degC] - outlet temperture of water
+deltaT1=Thi-Tci;
+deltaT2=Tho-Tco;
+LMTD=(deltaT2-deltaT1)/(log(deltaT2/deltaT1));
+Ai=qtotal/((Ui*LMTD));
+printf("\n\n (b) counter flow \n Ai = %f m^2",Ai);
+// (c) - 1-2 shell and tube
+Thi=120; //[degC] - inlet temperature of hydrocarbon
+Tho=65; //[degC] - outlet temperature of hydrocarbon
+Tci=15; //[degC] - inlet temperature of water
+Tco=50; //[degC] - outlet temperture of water
+Z=(Thi-Tho)/(Tco-Tci);
+nh=(Tco-Tci)/(Thi-Tci);
+deltaT1=Thi-Tco;
+deltaT2=Tho-Tci;
+F=0.92;
+LMTD=(F*(deltaT2-deltaT1))/(log(deltaT2/deltaT1));
+Ai=qtotal/((Ui*LMTD));
+printf("\n\n (c) 1-2 shell and tube \n Ai = %f m^2",Ai);
+// (d) - 2-4 shell and tube
+Thi=120; //[degC] - inlet temperature of hydrocarbon
+Tho=65; //[degC] - outlet temperature of hydrocarbon
+Tci=15; //[degC] - inlet temperature of water
+Tco=50; //[degC] - outlet temperture of water
+Z=(Thi-Tho)/(Tco-Tci);
+nh=(Tco-Tci)/(Thi-Tci);
+F=0.975;
+LMTD=(F*(deltaT2-deltaT1))/(log(deltaT2/deltaT1));
+Ai=qtotal/((Ui*LMTD));
+printf("\n\n (d) 2-4 shell and tube \n Ai = %f m^2",Ai);
+
+