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+clc;
+warning("off");
+printf("\n\n example10.5 - pg417");
+// given
+L=300; //[m] - length of pipe
+d=0.06; //[m] - inside diameter
+deltap=147*10^3; //[Pa] - pressure the pump can supply
+ebyd=0.000762; // relative roughness
+p=1000; //[kg/m^3] - density
+mu=1*10^-3; //[kg/m*sec] - viscosity
+tauw=(d*(deltap))/(4*L);
+// using the hit and trial method for estimation of flow velocity
+// let
+f=0.005;
+U=((2*tauw)/(p*f))^(1/2);
+Nre=(d*U*p)/mu;
+// from the graph value of f at the above calculated reynolds no. and the given relative roughness(e/d)
+f=0.0054;
+U=((2*tauw)/(p*f))^(1/2);
+Nre=(d*U*p)/mu;
+// from the graph value of f at the above calculated reynolds no. and the given relative roughness(e/d)
+f=0.0053;
+U=((2*tauw)/(p*f))^(1/2);
+Nre=(d*U*p)/mu;
+// from the graph value of f at the above calculated reynolds no. and the given relative roughness(e/d)
+f=0.0053;
+// At this point the value of f is deemed unchanged from the last iteration .Hence, the values obtained after the third iteration are the converged values
+printf("\n\n The maximum flow velocity is \n U=%f m/sec",U);
+