5 files changed, 138 insertions, 0 deletions
diff --git a/881/CH24/EX24.1/exa24_1.sce b/881/CH24/EX24.1/exa24_1.sce
new file mode 100755
index 000000000..3ae33f252
--- /dev/null
+++ b/881/CH24/EX24.1/exa24_1.sce
@@ -0,0 +1,21 @@
+clc;
+//Example 24.1
+//Page No 981
+
+
+
+//soution
+
+f=18*10^9;
+D=16*10^3;
+c=3*10^8
+
+disp("free space path loss based on inverse square law, which yields, ");
+
+lp=((4*%pi*D*f)/c)^2;
+
+disp(lp,"Lp = ");
+
+Lp=10*log10(lp);
+
+disp('db',Lp,"Lp(dB) = ");
diff --git a/881/CH24/EX24.2/exa24_2.sce b/881/CH24/EX24.2/exa24_2.sce
new file mode 100755
index 000000000..8c15152a6
--- /dev/null
+++ b/881/CH24/EX24.2/exa24_2.sce
@@ -0,0 +1,27 @@
+clc;
+//Example 24.2
+//Page No 988
+
+disp("Given: d1=18.6Km, d=14.4Km, Hn=H1=200meters, n=1");
+
+//solution
+
+d1=18.6; 
+d=14.4; 
+H1=0.2;
+n=1;
+c=3*10^8;
+
+disp("From equation 24-10, the height of the nth fresnel zone Hn is, ");
+
+l=(((H1^2)*d)/(n*d1*(d1-d)));
+
+l=l*10^3;
+
+disp('m',l,"l = ")
+
+f=(c/l);
+
+f=f/10^6;
+
+disp('MHz',f,"f = ");
diff --git a/881/CH24/EX24.3/exa24_3.sce b/881/CH24/EX24.3/exa24_3.sce
new file mode 100755
index 000000000..26691996f
--- /dev/null
+++ b/881/CH24/EX24.3/exa24_3.sce
@@ -0,0 +1,27 @@
+clc;
+//Example 24.3
+//Page No 988
+
+disp("Given: Noise bandwidth is 10MHz");
+
+//solution
+
+f=10*10^6;
+
+disp("Substituting in equation 24-16 yields, ");
+
+N=-174+(10*log10(f));
+
+disp('dBm',N,"N = ");
+
+disp("If the minimum C/N requirement for a receiver ");
+
+Cmin=24+N;
+
+disp('dBm',Cmin,"N = ");
+
+disp("For a system gain of 113.35dB, it would require a minimum transmit carrier power(Pt) of ")
+
+Pt=113.35+Cmin;
+
+disp('dBm',Pt,"N = ");
diff --git a/881/CH24/EX24.4/exa24_4.sce b/881/CH24/EX24.4/exa24_4.sce
new file mode 100755
index 000000000..dbfaa4c17
--- /dev/null
+++ b/881/CH24/EX24.4/exa24_4.sce
@@ -0,0 +1,21 @@
+clc;
+//Example 24.4
+//Page No 990
+
+disp("Given: Refer to figure");
+
+//solution
+
+disp("To achieve a S/N ratio of 32dB out of the FM demodulator, an input C/N of 15dB is required. Solving the receiver input carrier to noise ratios give, ");
+
+Cmin=15+6.5
+
+disp('dB',Cmin,"Cmin/N = ");
+
+cmin=Cmin+(-104);
+
+disp('dBm',cmin,"Cmin = ");
+
+Pt=112+cmin;
+
+disp('dBm',Pt,"Pt = ");
diff --git a/881/CH24/EX24.5/exa24_5.sce b/881/CH24/EX24.5/exa24_5.sce
new file mode 100755
index 000000000..cf835511d
--- /dev/null
+++ b/881/CH24/EX24.5/exa24_5.sce
@@ -0,0 +1,42 @@
+clc;
+//Example 24.5
+//Page No 990
+
+disp("Given: The system is shown in figure.");
+
+//solution
+
+cn=23;
+NF=4.42;
+B=68;
+
+disp("The minimum C/N at the input to the FM receiver is 23dB, ");
+
+cmin=cn+NF;
+
+disp('dB',cmin,"CMin/N = ");
+
+disp("Substituting into equation 24-16 yields, ");
+
+N=-174+B;
+
+disp('dBm',N,"N = ");
+
+Cmin=cmin+N;
+
+disp('dBm',Cmin,"Cmin = ");
+
+disp("Substituting into equation 24-14 yields, ");
+
+Fm=((30*log10(50))+10*(log10(6*0.25*0.125*8))-(10*log10(1-0.99999))-70);
+
+disp('dB',Fm,"Fm = ");
+
+disp("Substituting into equation 24-8 yields, ");
+
+Lp=92.4+(20*log10(8))+(20*log10(50));
+
+disp('dB',Lp,"Lp = ");
+
+disp("          At=Ar= 37.8 dB","          Lf = 4.875","          Lb = 4 dB","From Table 24-3");
+