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+clc
+//initialisation of variables
+d= 2 //m
+t= 20 //mm
+p= 1.5 //N/mm^2
+load= 2500 //KN
+alpha= 60 //degrees
+//CALCULATIONS
+Cs= (p*d*10^3)/(2*t)
+Ls= (p*d*10^3)/(4*t)
+Ds= (load*10^3)/(%pi*d*t*10^3)
+Ts= Ls+Ds
+sigman= (Ts*t*(cosd(90-alpha))^2+Cs*t*(cosd(alpha))^2)/t
+tab= Ts*sind(alpha)*cosd(alpha)-Cs*sind(alpha)*cosd(alpha)
+tmax= (Ts-Cs)/2
+//RESULTS
+printf ('direct stress= %.1f N/mm^2',sigman)
+printf (' \n Shear stress=%.1f N/mm^2',tab)
+printf (' \n maximum Shear stress=%.1f N/mm^2',tmax)