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+//Example 3.9
+clc
+clear
+
+A = [1 1 1; 4 3 -1; 3 5 3];
+n = length (A(1,:));
+Aug = [A,eye(n,n)];
+
+// Forward Elimination
+for j = 1:n-1
+    for i = j+1:n
+        Aug(i,j:2*n) = Aug(i,j:2*n) - Aug(i,j) / Aug(j,j) * Aug(j,j:2*n);
+    end
+end
+
+// Backward Elimination
+for j = n:-1:2
+    Aug(1:j-1,:) = Aug(1:j-1,:) - Aug(1:j-1,j) / Aug(j,j) * Aug(j,:);
+end
+
+// Diagonal Normalization
+for j=1:n
+    Aug(j,:) = Aug(j,:) / Aug(j,j);
+end
+Inv_A = Aug(:,n+1:2*n);
+disp(Inv_A,"Inverse of A (A-1) = ")