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+//clear//
+//Example3.14:DTFS
+//Finding x[n] using parseval's relation of DTFS
+clear;
+close;
+clc;
+N = 6;
+n = 0:N-1;
+a(1) = 1/3;
+a(2)=0;
+a(4)=0;
+a(5)=0;
+a1 = (1/6)*((-1)^n);
+x =0;
+for k = 0:N-2
+  if(k==2)
+    x = x+a1;
+  else
+    x =  x+a(k+1);
+  end
+end
+x = [x($:-1:1),x(2:$)];
+n = -(N-1):(N-1);
+//
+figure
+a = gca();
+a.y_location = "origin";
+a.x_location = "origin";
+plot2d3('gnn',n,x,5)
+poly1 = a.children(1).children(1);
+poly1.thickness = 3; 
+title('x[n]')
+xlabel('                                                       n')