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-rwxr-xr-x83/CH8/EX8.1/example_8_1.sce18
-rwxr-xr-x83/CH8/EX8.1/result_example_8_1.txt8
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+//Chapter 8
+//Example 8.1
+//page 300
+//To determine the change in the frequency
+clear;clc;
+f=50;
+H=5e3;
+KE=H*100*1000; //K.E stored in the generator
+PI=50e6; //power input to generator before the stem valve is closed
+EE=PI*0.4 ; //Excess energy input to the rotating parts
+fnew=f*((KE+EE)/KE)^0.5; //frequency at the end of the 0.4sec
+printf('\nKinetic Energy stored in the rotating parts of generator and turbine = %d kW-sec',KE/1000);
+printf('\nExcess power input to generator before the stem valve begins to close=%d MW',PI/1000000);
+printf('\nExcess energy input to rotating parts in 0.4sec=%d kW-sec',EE/1000);
+printf('\nFrequency at the end of 0.4sec=%0.2f Hz\n\n',fnew);
+
+
+
diff --git a/83/CH8/EX8.1/result_example_8_1.txt b/83/CH8/EX8.1/result_example_8_1.txt
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+
+
+Kinetic Energy stored in the rotating parts of generator and turbine = 500000 kW-sec
+Excess power input to generator before the stem valve begins to close=50 MW
+Excess energy input to rotating parts in 0.4sec=20000 kW-sec
+Frequency at the end of 0.4sec=50.99 Hz
+
+