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+
+-->exec('/home/samyak/scilab_working_directory/chapter_6/ex_1/example_6_1.sce', -1)
+Let us solve this problem by giving values given in the table 6.1 instead of keeping it in variables
+
+ Ybus matrix using singular transformation for the system of fig.6.2 is
+ Ybus=
+ 4. - 9.i - 2. + 6.i - 1. + 3.i 0
+ - 2. + 6.i 4.666 - 11.i - 0.666 + 2.i - 1. + 3.i
+ - 1. + 3.i - 0.666 + 2.i 4.666 - 11.i - 2. + 6.i
+ 0 - 1. + 3.i - 2. + 6.i 4. - 9.i
+
+
+ For verification,calculating Ybus substituting as given in the text book
+ Ybus(verifiaction)=
+ 4. - 9.i - 2. + 6.i - 1. + 3.i 0
+ - 2. + 6.i 4.666 - 11.i - 0.666 + 2.i - 1. + 3.i
+ - 1. + 3.i - 0.666 + 2.i 4.666 - 11.i - 2. + 6.i
+ 0 - 1. + 3.i - 2. + 6.i 4. - 9.i
+
+-->diary(0);