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+-->//(Design against Static Load) Example 4.18
+ 
+-->//Refer Fig.4.57 on page 126
+ 
+-->//Tensile yield strength of FeE250 Syt (N/mm2)
+ 
+-->Syt = 250
+ Syt  =
+ 
+    250.  
+ 
+-->//Factor of safety fs
+ 
+-->fs = 5
+ fs  =
+ 
+    5.  
+ 
+-->//Diameter of bars to be sheared D (mm)
+ 
+-->D = 6.25
+ D  =
+ 
+    6.25  
+ 
+-->//Ultimate shear strength of the material Sus (N/mm2)
+ 
+-->Sus = 350
+ Sus  =
+ 
+    350.  
+ 
+-->//Permissible bearing pressure on the pins p (N/mm2)
+ 
+-->p = 10
+ p  =
+ 
+    10.  
+ 
+-->//Pin length to diameter ratio r1
+ 
+-->r1 = 1.25
+ r1  =
+ 
+    1.25  
+ 
+-->//Link cross-section width to thickness ratio r2 
+ 
+-->r2 = 2
+ r2  =
+ 
+    2.  
+ 
+-->//Distance between pinA and pinB l1 (mm)
+ 
+-->l4 = 400
+ l4  =
+ 
+    400.  
+ 
+-->//Distance between bar to be sheared and pinA & force application point and pinC l2 (mm)
+ 
+-->l2 = 100
+ l2  =
+ 
+    100.  
+ 
+-->//Distance between the force applied and pinD l3 (mm)
+ 
+-->l3 = 1000
+ l3  =
+ 
+    1000.  
+ 
+-->//Thickness of gunmetal bush over pin C t (mm)
+ 
+-->t = 2.5
+ t  =
+ 
+    2.5  
+ 
+
+Diameter of pins(d1) = 15.000000 mm
+
+Length of pins(l1) = 20.000000 mm
+
+Diameter of link(d) = 10.000000 mm
+
+Width of lever cross-section(h) = 40.000000 mm
+
+Thickness of lever cross-section(b) = 20.000000 mm
+
+The design is safe
+ 
+\ No newline at end of file