7 files changed, 0 insertions, 121 deletions
diff --git a/746/CH3/EX3.01/3_01.jpg b/746/CH3/EX3.01/3_01.jpg
deleted file mode 100755
index 74d8becc0..000000000
--- a/746/CH3/EX3.01/3_01.jpg
+++ /dev/null
diff --git a/746/CH3/EX3.01/3_01.sce b/746/CH3/EX3.01/3_01.sce
deleted file mode 100755
index 089d4a614..000000000
--- a/746/CH3/EX3.01/3_01.sce
+++ /dev/null
@@ -1,21 +0,0 @@
-//liquid level//
-pathname=get_absolute_file_path('3.01.sce')
-filename=pathname+filesep()+'3.01-data.sci'
-exec(filename)
-//Tube diameter(in mm):
-D=1:25;
-D1=D/1000
-[m n]=size(D1)
-for i=1:n
-//Change in liquid level for water(in mm):
-dhw(i)=4*STw*cosd(thetaw)/dw/g/D1(i);
-//Change in liquid level for mercury(in mm):
-dhm(i)=4*STm*cosd(thetam)/dm/g/D1(i);
-end;
-
-//Plotting tube daimeter and water level:
-plot(D1*1000,dhw,'-o')
-//Plotting tube daimeter and mercury level:
-plot(D1*1000,dhm,'-*')
-legend(['Water';'Mercury']);
-xtitle('Liquid level vs Tube diameter','Liquid level(in mm)','Tube diameter(in mm)')
diff --git a/746/CH3/EX3.03/3_03.sce b/746/CH3/EX3.03/3_03.sce
deleted file mode 100755
index 92dc4e6bd..000000000
--- a/746/CH3/EX3.03/3_03.sce
+++ /dev/null
@@ -1,8 +0,0 @@
-//pressure difference//
-pathname=get_absolute_file_path('3.03.sce')
-filename=pathname+filesep()+'3.03-data.sci'
-exec(filename)
-//Pressure difference(in lbf/in^2):
-dp=g*d*(-d1+SGm*d2-SGo*d3+SGm*d4+d5)/12/144
-printf("\n\nRESULTS\n\n")
-printf("\n\nPressure difference between A and B: %f lbf/in^2\n\n",dp)
diff --git a/746/CH3/EX3.04/3_04.sce b/746/CH3/EX3.04/3_04.sce
deleted file mode 100755
index 4030fcd51..000000000
--- a/746/CH3/EX3.04/3_04.sce
+++ /dev/null
@@ -1,40 +0,0 @@
-//temperature and pressure//
-pathname=get_absolute_file_path('3.04.sce')
-filename=pathname+filesep()+'3.04-data.sci'
-exec(filename)
-//Assuming temperature varies linearly with altitude:
-//Temperature gradient(in F/ft):
-m=(T1-T2)/(z2-z1)
-//Value of g/(m*R):
-v=g/m/R/32.2
-//Pressure at Vail Pass(in inches of Hg):
-p12=p1*((T2+460)/(T1+460))^v
-//Percentage change in density:
-pc1=(p12/p1*(T1+460)/(T2+460)-1)*100
-//Assuming density is constant:
-//Pressure at Vail Pass(in inches of Hg):
-p22=p1*(1-(g*(z2-z1)/(R*32.2)/(T1+460)))
-//Percentage change in density:
-pc2=0;
-//Assuming temperature is constant:
-//Pressure at Vail Pass(in inches of Hg):
-p32=p1*%e^(-g*(z2-z1)/(R*32.2)/(T2+460))
-//Percentage change in density:
-pc3=(p32/p1*(T1+460)/(T1+460)-1)*100
-//For an adiabatic atmosphere:
-p42=p1*((62+460)/(80+460))^(k/(k-1))
-//Percentage change in density:
-pc4=(p42/p1*(T1+460)/(T2+460)-1)*100
-printf("\n\nRESULTS\n\n")
-printf("\n\n1) If temperature varies linearly with altitude\n\n")
-printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p12)
-printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc1)
-printf("\n\n2) If density is constant\n\n")
-printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p22)
-printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc2)
-printf("\n\n3) If temperature is constant\n\n")
-printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p32)
-printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc3)
-printf("\n\n4) For an adiabatic atmosphere\n\n")
-printf("\n\n\tAtmospheric pressure at Vail Pass: %f inches of Hg\n\n",p42)
-printf("\n\n\tPercentage change in density wrt Denver: %f percent\n\n",pc4)
diff --git a/746/CH3/EX3.05/3_05.sce b/746/CH3/EX3.05/3_05.sce
deleted file mode 100755
index 4cea618b9..000000000
--- a/746/CH3/EX3.05/3_05.sce
+++ /dev/null
@@ -1,25 +0,0 @@
-//force and pressure//
-pathname=get_absolute_file_path('3.05.sce')
-filename=pathname+filesep()+'3.05-data.sci'
-exec(filename)
-//Net force on the gate(in kN):
-Fr=d*g*w*(D*L+L^2/2*sind(theta))
-//Centre of pressure:
-//Calculation for y coordinate:
-   yc=D/sind(theta)+L/2
-   //Area(in m^2):
-   A=L*w
-   //Moment of inertia of rectangular gate(in m^4):
-   Ixx=w*L^3/12
-   //y coordinate(in m):
-   y=yc+Ixx/A/yc
-//Calculation for x coordinate:
-   Ixy=0
-   xc=w/2
-   //x coordinate(in m):
-   x=xc+Ixy/A/xc
-printf("\n\nRESULTS\n\n")
-printf("\n\nNet force on the gate: %f kN\n\n",Fr/1000)
-printf("\n\nCoordinate of centre of pressure:(%0.1f,%0.1f)\n\n",x,y)
-       
-      
diff --git a/746/CH3/EX3.06/3_06.sce b/746/CH3/EX3.06/3_06.sce
deleted file mode 100755
index 89f2daf73..000000000
--- a/746/CH3/EX3.06/3_06.sce
+++ /dev/null
@@ -1,9 +0,0 @@
-//force//
-pathname=get_absolute_file_path('3.06.sce')
-filename=pathname+filesep()+'3.06-data.sci'
-exec(filename)
-//Force required to keep the door shut(in lbf):
-function y=f(z),y=b/L*p0*z+d*b/L*(L*z-z^2),endfunction
-Ft=intg(0,L,f)
-printf("\n\nRESULTS\n\n")
-printf("\n\nForce requiredto kep the door shut: %.1f lbf\n\n",Ft)
diff --git a/746/CH3/EX3.07/3_07.sce b/746/CH3/EX3.07/3_07.sce
deleted file mode 100755
index 8624fca4a..000000000
--- a/746/CH3/EX3.07/3_07.sce
+++ /dev/null
@@ -1,18 +0,0 @@
-//force at equilibrium//
-pathname=get_absolute_file_path('3.07.sce')
-filename=pathname+filesep()+'3.07-data.sci'
-exec(filename)
-//Horizontal component of resultant force(in kN):
-Frh=0.5*d*g*w*D^2
-//Line of action of Frh(in m):
-y1=0.5*D+w*D^3/12/(0.5*D)/(w*D)
-//Vertical component of resultant force(in kN):
-function y=q(x), y=d*g*w*(D-sqrt(a*x)),endfunction
-Frv=intg(0,D^2/a,q)
-//Line of acion of Frv(in m):
-function k=f(x), k=d*g*w/Frv*x*(D-sqrt(a*x)),endfunction
-xa=intg(0,D^2/a,f)
-//Force required to keep the gate in equilibrium(in kN):
-Fa=1/l*(xa*Frv+(D-y1)*Frh)
-printf("\n\nRESULTS\n\n")
-printf("\n\nForce required to keep the gate at equilibrium: %f kN\n\n",Fa/1000)