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+//Chapter 7_Operational Amplifier Characteristics
+//Caption : Bipolar Differential Amplifier Parameter
+//Example7.1: The following specification are given for the dual input,balanced output bipolar diferential amplifier:
+//Rc=2.2 kOhm,Re=4/7kOhm,Rs=50 ohm,Vcc=10V,Vee=-10V and Bf=Bo=100. Assume      Vbe=0.7V.
+//Determine
+//a)Icq and Vceq
+//b)Differential-mode voltage fgain , and
+//c)Input and output resistances.
+clear;
+clc;
+//a)Solution:\
+Rc=2.2*10^3;// collector resistance in one transistor in ohm
+Re=4.7*10^3;// emitte resitance of one transistor in ohm
+Rs=50;//base or source resitance of one transistor in ohm
+Vcc=10;// collector power supply in Volt
+Vee=-10;// negative emitter power supply
+Bf=100;// gain of the transistor
+Bo=Bf;
+Vbe=0.7;//base emitter voltage of one transiator
+Icq=(abs(Vee)-Vbe)/(2*Re+(Rs/Bf));
+Vceq=Vcc+Vbe-Rc*Icq;
+//b)Solution:
+gm=Icq/(25*10^-3);// where transconductance gm=Ic/Vt, Vt=25mV at room temperature, so  gm =Ic/25
+Ad=-gm*Rc;// differential mode voltage gain Icq here will be taken as found above  not approximated to as given book
+//c)Solution:
+r=Bo/gm;// input resistance of one transistor
+Ri=2*r;//differential mode input resistance
+Ro=Rc;//differential mode output resistance
+disp('A',Icq*10^3,'operating point collector current')
+disp('V',Vceq,'collector-to-emitter voltage is:')
+disp(abs(Ad),'Differential-mode voltage gain')
+disp('kilo Ohm',Ri/10^3,'Input Resistance')
+disp('kilo Ohm',Ro/10^3,'Output Resistance')
+// Note:
+//value of  Icq is taken as 0.0009893 A or 0.9893 mA not approximated to 0.98 mA
+\ No newline at end of file