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+//Chapter 15_Phase Locked Loops
+//Caption : Output Signal Frequency
+//Example 15.2: A PLL has a Ko of 2*%pi(1kHz)/V, a Kv of 500 per sec, and a free running frequency of 500Hz.
+//a) For a constant input signal frequency of 250 Hz and 1kHz.find vf.
+clear;
+clc;
+//a)Solution:
+Ko=2*%pi*10^3;// VCO gain in kHz/V
+Kv=500;//loop bandwith in per second
+Wc=500;//Free running frequency of VCO in PLL or 2*%pi*500
+//Wi=angular input signal  frequency in Hz
+//Wo=angular output signal frequency in Hz
+//since vf=(Wo(t)-Wc)/Ko
+//under locked condition Wo=Wi, so vf=(Wo-Wc)/Ko
+for i=1:2,
+    if i==1 then 
+        Wo=250;
+        //or 
+        Fo=2*%pi*Wo;//in Hz
+vf=(Fo-2*%pi*500)/Ko;
+disp('********For input signal frequency W=250 Hz********')
+disp('V',vf,'output signal voltage of PLL for  Wo=250 Hz is:')
+else
+    Wo=1000;
+    Fo=2*%pi*Wo;//in Hz
+    vf=(Fo-2*%pi*500)/Ko;
+    disp('********For input signal frequency Wo=1 kHz********')
+    disp('V',vf,'output signal voltage of PLL for  Wo=1kHz is:')
+end
+end
+\ No newline at end of file