diff options
Diffstat (limited to '698/CH2/EX2.12/P12_stresses_in_locomotive.sce')
-rw-r--r-- | 698/CH2/EX2.12/P12_stresses_in_locomotive.sce | 82 |
1 files changed, 82 insertions, 0 deletions
diff --git a/698/CH2/EX2.12/P12_stresses_in_locomotive.sce b/698/CH2/EX2.12/P12_stresses_in_locomotive.sce new file mode 100644 index 000000000..99cab88cd --- /dev/null +++ b/698/CH2/EX2.12/P12_stresses_in_locomotive.sce @@ -0,0 +1,82 @@ +clc
+//Example 2.12
+//Stresses in a locomotive
+//------------------------------------------------------------------------------
+
+//Given Data:
+
+//Speed
+
+V=96.6 //kmph
+
+//Crank length
+Cl=0.375 // m
+//Length of side rod
+L=2 // m
+//Radius of driver
+R=0.915 // m
+
+//Tractive effort per wheel
+Et=45000 // N
+//Weight of the rod
+Wl=90 // kg/m
+//Total weight
+Wt=Wl*L // kg
+
+//Cross section of rod
+b= 0.075 // m
+t= 0.15 // m
+
+//------------------------------------------------------------------------------
+res12=mopen(TMPDIR+'12_stresses_in_locomotive.txt','wt')
+
+//angular speed of wheels
+omega=((V*5)/18)/R
+
+mfprintf (res12,"The angular speed of wheels is %0.1f rad/s\n",omega)
+mfprintf (res12,"All points on the side rod have a downward acceleration ap\n")
+mfprintf(res12,"The locomotive is moving with uniform velocity, therefore acceleration ao=0\n\n")
+
+//Acceleration
+apo=Cl* omega^2
+mfprintf(res12,"\tap=ao+apo\n\t =apo=%0.2fm/s^2\n\n",apo)
+
+//Inertai Force
+Fi=Wt*apo
+mfprintf(res12,"Inertia force acting upward on the rod, Fi=%0.2f N\n\n",Fi)
+
+//Net upward force
+W=Fi-(Wt*9.81)
+mfprintf(res12,"Net force acting upward on the rod, Fup=%0.2f N\n\n",W)
+
+mfprintf(res12,"Axial force F can be determined by assuming rear wheel\nand rod as free bodies and taking moments about centre of wheel.\n")
+
+mfprintf(res12,"\tCl*F= Et*R\n")
+
+F=(Et*R)/Cl
+
+mfprintf(res12,"The axial force F is %0.2f N\n\n",F)
+
+mfprintf(res12,"Maximum bending moment for simple beam carrying unifornmly distributed load is\n\t")
+mfprintf(res12,"(W*L)/8\n\n")
+
+M=(W*L)/8
+
+mfprintf(res12,"Normal Stress \n\tSx= (P/A) + (M*c)/I\n\n")
+P=F
+A=b*t
+c=b
+I=(b* (t^3))/12
+Sx= (P/A) + (M*c)/I
+
+Sn_max = Sx
+Tmax = Sx/2
+
+mfprintf(res12,"The maximum normal stress is \n\tSn_max = Sx = %0.1f MN/m^2\n\n",Sn_max* 10^-6)
+
+mfprintf(res12,"The maximum shear stress is \n\tTmax = Sx/2 = %0.1f MN/m^2",Tmax* 10^-6)
+
+mclose(res12)
+editor(TMPDIR+'12_stresses_in_locomotive.txt')
+//------------------------------------------------------------------------------
+//---------------------------End of Program-------------------------------------
\ No newline at end of file |