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+clear;
+clc;
+
+// Example: 9.1
+// Page: 338
+
+printf("Example: 9.1 - Page: 338\n\n");
+
+// Solution
+
+//*****Data******//
+V1_bar = 52.37*10^(-6);// [partial molar volume of ethanol, cubic m/mol]
+y1 = 0.5;// [mole fraction of ethanol]
+Density = 800.21;// [kg/cubic m]
+M1 = 46*10^(-3);// //[Molecular wt. of ethanol,kg/mol]
+M2 = 18*10^(-3);// [Molecular wt. of water,kg/cmol]
+//*************//
+
+y2 = 1 - y1;// [mole fraction of water]
+M = y1*M1 + y2*M2;// [Molecular wt. of mixture, kg/mol]
+V = M/Density;// [Volume of mixture, cubic m/mol]
+// From Eqn. 9.9:
+V2_bar = (V - y1*V1_bar)/y2;// [partial molar volume of water, cubic m/mol]
+printf("Partial molar volume of water is %.2e cubic m/mol\n",V2_bar);
+\ No newline at end of file