diff options
Diffstat (limited to '647/CH8')
-rwxr-xr-x | 647/CH8/EX8.1/Example8_1.sce | 27 | ||||
-rwxr-xr-x | 647/CH8/EX8.10/Example8_10.sce | 42 | ||||
-rwxr-xr-x | 647/CH8/EX8.2/Example8_2.sce | 27 | ||||
-rwxr-xr-x | 647/CH8/EX8.3/Example8_3.sce | 20 | ||||
-rwxr-xr-x | 647/CH8/EX8.4/Example8_4.sce | 20 | ||||
-rwxr-xr-x | 647/CH8/EX8.5/Example8_5.sce | 19 | ||||
-rwxr-xr-x | 647/CH8/EX8.6/Example8_6.sce | 35 | ||||
-rwxr-xr-x | 647/CH8/EX8.7/Example8_7.sce | 35 | ||||
-rwxr-xr-x | 647/CH8/EX8.8/Example8_8.sce | 41 | ||||
-rwxr-xr-x | 647/CH8/EX8.9/Example8_9.sce | 23 |
10 files changed, 289 insertions, 0 deletions
diff --git a/647/CH8/EX8.1/Example8_1.sce b/647/CH8/EX8.1/Example8_1.sce new file mode 100755 index 000000000..516ac7fc3 --- /dev/null +++ b/647/CH8/EX8.1/Example8_1.sce @@ -0,0 +1,27 @@ +clear;
+clc;
+
+// Example: 8.1
+// Page: 297
+
+printf("Example: 8.1 - Page: 297\n\n");
+
+// Solution
+
+//*****Data******//
+Tl = 273 - 4;// [K]
+Th = 273 + 30;// [K]
+Ql = 30;// [kW]
+//*************//
+
+// Solution (a)
+COP = Tl/(Th - Tl);
+printf("The coeffecient of performance of the cycle is %.2f\n",COP);
+
+// Solution (b)
+Wnet = Ql/COP;// [kW]
+printf("The power required is %.2f kW\n",Wnet);
+
+// Solution (c)
+Qh = Wnet + Ql;// [kW]
+printf("The rate of heat rejection in the room is %.2f kW",Qh);
\ No newline at end of file diff --git a/647/CH8/EX8.10/Example8_10.sce b/647/CH8/EX8.10/Example8_10.sce new file mode 100755 index 000000000..bce25e4d2 --- /dev/null +++ b/647/CH8/EX8.10/Example8_10.sce @@ -0,0 +1,42 @@ +clear;
+clc;
+
+// Example: 8.10
+// Page: 313
+
+printf("Example: 8.10 - Page: 313\n\n");
+
+// Solution
+
+//*****Data******//
+Q = 5;// [tons]
+T1 = 253;// [Temperature of the working fluid leaving the evaporator, K]
+T2 = 303;// [Temperature of the working fluid leaving the evaporator, K]
+T3 = 303;// [K]
+Pressure_Ratio = 4;
+C = 1.008;// [kJ/kg]
+gama = 1.4;
+//**************//
+
+// Solution (a)
+T2 = T1*((Pressure_Ratio)^((gama - 1)/gama));// [K]
+T2 = T1*(Pressure_Ratio)^((gama - 1)/gama);// [K]
+T4 = T3/((Pressure_Ratio)^((gama - 1)/gama));// [K]
+COP = T1/(T2 - T1);
+printf("COP of Air Refrigeration System is %.2f\n",COP);
+
+// Solution (b)
+mdot = Q*12660/(C*(T1 - T4));// [kg/h]
+printf("Mass flow rate of the refrigerant is %.2f kg/h\n",mdot);
+
+// Solution (c)
+Wcompression = mdot*C*(T2 - T3);// [kJ/h]
+printf("The work of Compression is %.2f kW\n",Wcompression/3600);
+
+// Solution (d)
+Wexpansion = mdot*C*(T1 - T4);// [kJ/h]
+printf("The work of expansion is %.2f kW\n",Wexpansion/3600);
+
+// Solution (e)
+Wnet = Wcompression - Wexpansion;// [kJ/h]
+printf("Net work of the system is %.2f kW\n",Wnet/3600);
\ No newline at end of file diff --git a/647/CH8/EX8.2/Example8_2.sce b/647/CH8/EX8.2/Example8_2.sce new file mode 100755 index 000000000..8f028888f --- /dev/null +++ b/647/CH8/EX8.2/Example8_2.sce @@ -0,0 +1,27 @@ +clear;
+clc;
+
+// Example: 8.2
+// Page: 298
+
+printf("Example: 8.2 - Page: 298\n\n");
+
+// Solution
+
+//*****Data******//
+Tl = -10 + 273;// [K]
+Th = 45 + 273;// [K]
+Ql = 1;// [ton]
+//*************//
+
+// Solution (a)
+COP = Tl/(Th - Tl);
+Wnet = Ql*3.516/COP;// [kW]
+printf("The power consumption is %.3f kW\n",Wnet);
+
+// Solution (b)
+Tl = -20 + 273;// [K]
+Th = 45 + 273;// [K]
+COP = Tl/(Th - Tl);
+Ql = Wnet*COP;// [kW]
+printf("Cooling Effect produced is %.3f kW\n",Ql);
\ No newline at end of file diff --git a/647/CH8/EX8.3/Example8_3.sce b/647/CH8/EX8.3/Example8_3.sce new file mode 100755 index 000000000..865dbb4d4 --- /dev/null +++ b/647/CH8/EX8.3/Example8_3.sce @@ -0,0 +1,20 @@ +clear;
+clc;
+
+// Example: 8.3
+// Page: 298
+
+printf("Example: 8.3 - Page: 298\n\n");
+
+// Solution
+
+// From Example 8.2:
+
+// For refrigerated space:
+// Wnet = Ql/4.78 = 0.209*Ql;
+
+// For freezer box.
+// Wnet = Ql/3.89 = 0.257*Ql
+
+percent = ((0.257 - 0.209)/0.209)*100;
+printf("Increase in percentage of work output is %.2f %%",percent);
\ No newline at end of file diff --git a/647/CH8/EX8.4/Example8_4.sce b/647/CH8/EX8.4/Example8_4.sce new file mode 100755 index 000000000..36ade8c4c --- /dev/null +++ b/647/CH8/EX8.4/Example8_4.sce @@ -0,0 +1,20 @@ +clear;
+clc;
+
+// Example: 8.4
+// Page: 299
+
+printf("Example: 8.4 - Page: 299\n\n");
+
+// Solution
+
+//*****Data******//
+Th = 273 + 24;// [K]
+Tl = 0 + 273;// [K]
+Qh = 25;// [kW]
+//*************//
+
+COP = Th/(Th - Tl);
+Wnet = Qh/COP;// [kW]
+printf("Coeffecient of performance of Carnot Heat Pump is %.2f\n",COP);
+printf("Power input can be estimated as %.2f kW\n",Wnet);
\ No newline at end of file diff --git a/647/CH8/EX8.5/Example8_5.sce b/647/CH8/EX8.5/Example8_5.sce new file mode 100755 index 000000000..64f7c310c --- /dev/null +++ b/647/CH8/EX8.5/Example8_5.sce @@ -0,0 +1,19 @@ +clear;
+clc;
+
+// Example: 8.5
+// Page: 299
+
+printf("Example: 8.5 - Page: 299\n\n");
+
+// Solution
+
+//*****Data******//
+Tl = -2 + 273;// [K]
+Th = 20 + 273;// [K]
+Qh = 80000;// [kJ/h]
+//*************//
+
+Ql = Qh*Tl/Th;// [kJ/h]
+Wnet = Qh - Ql;// [kJ/h]
+printf("Minimum Power input required is %.3f kW\n",Wnet/3600);
\ No newline at end of file diff --git a/647/CH8/EX8.6/Example8_6.sce b/647/CH8/EX8.6/Example8_6.sce new file mode 100755 index 000000000..80e6e365c --- /dev/null +++ b/647/CH8/EX8.6/Example8_6.sce @@ -0,0 +1,35 @@ +clear;
+clc;
+
+// Example: 8.6
+// Page: 303
+
+printf("Example: 8.6 - Page: 303\n\n");
+
+// Solution
+
+//*****Data******//
+Tl = 273;// [K]
+Th = 313;// [K]
+H1 = 187;// [Enthalpy of saturated vapour at 273 K, kJ/kg]
+H3 = 74;// [Enthalpy of saturated liquid at 313 K,kJ/kg]
+H4 = H3;// [kJ/kg]
+H2 = 204;// [Enthalpy of Supersaturated Vapour at 273 K, kJ/kg]
+//****************//
+
+// Solution (i)
+// COP = Ql/Wnet;
+COP = ((H1 - H4)/(H2 - H1));
+printf("Enthalpy of saturated vapour is %.2f\n",COP);
+
+// Solution (ii)
+Ref_Effect = H1 - H4;// [kJ/kg]
+printf("Refrigerating Effect is %d kJ/kg\n",Ref_Effect);
+
+// Solution (iii)
+COP = Tl/(Th - Tl);
+printf("The COP of an ideal Carnot refrigerator is %.2f\n",COP);
+
+// Solution (iv)
+W = H2 - H1;// [kJ/kg]
+printf("Work done by the compression is %.2f kJ/kg\n",W);
\ No newline at end of file diff --git a/647/CH8/EX8.7/Example8_7.sce b/647/CH8/EX8.7/Example8_7.sce new file mode 100755 index 000000000..9ccf891dd --- /dev/null +++ b/647/CH8/EX8.7/Example8_7.sce @@ -0,0 +1,35 @@ +clear;
+clc;
+
+// Example: 8.7
+// Page: 304
+
+printf("Example: 8.7 - Page: 304\n\n");
+
+// Solution
+
+//*****Data******//
+P1 = 0.18;// [MPa]
+T1 = -10 + 273;// [K]
+mdot = 0.06;// [kg/s]
+P2 = 1;// [MPa]
+T2 = 45 + 273;// [K]
+T = 273 + 29;// [K]
+P = 0.75;// [MPa]
+H1 = 245.16;// [Enthalpy of superheated vapour at -10 OC & 0.18 MPa, kJ/kg]
+H2 = 277.2;// [Enthalpy of superheated vapour at 45 OC & 1 MPa, kJ/kg]
+H3 = 92.22;// [Enthalpy of saturated liquid at 29 OC & 0.75 MPa, kJ/kg]
+H4 = H3;// [kJ/kg]
+//*************//
+
+// Solution (a)
+Ql = mdot*(H1 - H4);// [kW]
+printf("Amount of heat removed from cold space is %.2f kW\n",Ql);
+
+// Solution (b)
+Wnet = mdot*(H2 - H1);// [kW]
+printf("THe power input required is %.2f kW\n",Wnet);
+
+// Solution (c)
+COP = Ql/Wnet;
+printf("COP of refrigeration of cycle is %.2f\n",COP);
\ No newline at end of file diff --git a/647/CH8/EX8.8/Example8_8.sce b/647/CH8/EX8.8/Example8_8.sce new file mode 100755 index 000000000..da9b430b3 --- /dev/null +++ b/647/CH8/EX8.8/Example8_8.sce @@ -0,0 +1,41 @@ +clear;
+clc;
+
+// Example: 8.8
+// Page: 305
+
+printf("Example: 8.8 - Page: 305\n\n");
+
+// Solution
+
+//*****Data******//
+Ql = 5;// [tons]
+Tl = -10 + 273;// [K]
+Th = 35 + 273;// [K]
+eta = 0.85;
+H1 = 183.2;// [Enthalpy of saturated vapour at 263 K, kJ/kg]
+H2 = 208.3;// [Enthalpy of superheated vapour, kJ/kg]
+H3 = 69.5;// [Enthalpy of saturated vapour at 308 K, kJ/kg]
+H4 = H3;// [kJ/kg]
+//***************//
+
+// Solution (a)
+// Mass flow rate:
+Ql = Ql*3.516;// [kW]
+mdot = Ql/(H1 - H4);// [kW]
+printf("Mass flow rate of the refrigerant is %.4f kg/s\n",mdot);
+
+// Solution (b)
+W = H2 - H1;// [kJ/kg]
+Wnet = W*mdot/eta;// [kW]
+printf("Power consumption in the compression is %.2f kW\n",Wnet);
+
+// Solution (c)
+Qh = Ql + Wnet;// [kW]
+printf("The amount of heat rejected in the condenser is %.2f kW\n",Qh);
+
+// Solution (d)
+COP_VapourCompression = (H1 - H4)/(H2 - H1);
+COP_Carnot = Tl/(Th - Tl);
+COP_relative = COP_VapourCompression/COP_Carnot;
+printf("Relative COP is %.2f\n",COP_relative);
\ No newline at end of file diff --git a/647/CH8/EX8.9/Example8_9.sce b/647/CH8/EX8.9/Example8_9.sce new file mode 100755 index 000000000..37914fbff --- /dev/null +++ b/647/CH8/EX8.9/Example8_9.sce @@ -0,0 +1,23 @@ +clear;
+clc;
+
+// Example: 8.9
+// Page: 308
+
+printf("Example: 8.9 - Page: 308\n\n");
+
+// Solution
+
+//*****Data******//
+Th = 273 + 125;// [K]
+Tl = 273 - 5;// [K]
+Ts = 273 + 28;// [K]
+COP = 2;
+//*************//
+
+COP_absorption = (Tl/(Ts - Tl))*((Th - Ts)/Th);
+if (COP - 0.1) < COP_absorption | (COP + 0.1) > COP_absorption
+ printf("Claim is Valid and reasonable");
+else
+ printf("Claim is not Valid");
+end
\ No newline at end of file |