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+clear;
+clc;
+
+// Example: 7.8
+// Page: 279
+
+printf("Example: 7.8 - Page: 279\n\n");
+
+// Solution
+
+//*****Data******//
+P1 = 500;// [kPa]
+T1 = 623;// [K]
+mdot = 12;// [kg/s]
+P2 = 500;// [kPa]
+T2 = 523;// [K]
+Qdot = -120;// [kW]
+H1 = 3168;// [kJ/kg]
+H2 = 2976;// [kJ/kg]
+//************//
+
+Q = Qdot/mdot;// [kJ/kg]
+// By energy balance:
+// (deltaU^2/2) + g*deltaZ + deltaH = Q - Ws
+// Considering negligible change in P.E., deltaZ = 0 & Ws = 0.
+// (U2^2 - U1^2)/2 + deltaH = Q
+deltaH = H2 - H1;// [kJ/kg]
+// Neglecting inlet velocity.
+U2 = sqrt(2*(Q - deltaH)*1000);// [m/s]
+printf("Outlrt velocity is %.1f m/s\n",U2); \ No newline at end of file