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+clear;
+clc;
+
+// Example: 3.4
+// Page: 90
+
+printf("Example: 3.4 - Page: 90\n\n");
+
+// Solution
+
+//*****Data*****//
+T1 = 450 + 273;// [K]
+P1 = 3;// [bar]
+//***************//
+
+// Soluton(a)
+// From Fig. 3.7, (Page 90)
+// Since the weight remains the same, therefore, the final pressure is equal to the initial pressure.
+// Therefore it is a constant pressure process.
+P2 = P1;// [bar]
+// Volumetric Ratio:
+V2_by_V1 = 2.5/(2.5 + 2.5);
+// Applying ideal gas law & P1 = P2
+T2 = T1*V2_by_V1;// [K]
+printf("Final Temperature of the air when the piston reaches stop is %.1f K\n",T2);
+
+// Solution (b)
+// When the piston rests ot the stops, the pressure exerted by the weight, air & the atmosphere will be different. But there will beno further decrease in volume.
+// This is a constant volume process.
+T3 = 273 + 30;// [K]
+// Applying ideal gas law & V2 = V3
+P3 = T3*P2/T2;// [bar]
+printf("Pressure of air inside the cylinder is %.2f bar\n",P3);
+\ No newline at end of file