13 files changed, 293 insertions, 0 deletions
diff --git a/647/CH1/EX1.1/Example1_1.sce b/647/CH1/EX1.1/Example1_1.sce
new file mode 100755
index 000000000..7ec57d2f1
--- /dev/null
+++ b/647/CH1/EX1.1/Example1_1.sce
@@ -0,0 +1,24 @@
+clear;
+clc;
+
+// Example: 1.1
+// Page: 4
+
+// Solution
+
+printf("Example: 1.1 - Page: 4\n\n");
+
+//*****Data*****//
+g_Earth = 9.83;// [m/square s]
+F_Earth = 800;// [N]
+g_Moon = 3.2;// [m/square s]
+//************//
+
+// From the expression of force, the force on the man on the Eath's surface is given by:
+// F = m*g_Earth
+m = F_Earth/g_Earth;// [kg]
+
+// On the moon, the weight of the mass is equal to the force acting on the mass on the moon and is given by
+F_Moon = m*g_Moon;// [N]
+
+printf("Weight of the man on the moon is %f N\n",F_Moon);
+\ No newline at end of file
diff --git a/647/CH1/EX1.10/Example1_10.sce b/647/CH1/EX1.10/Example1_10.sce
new file mode 100755
index 000000000..3519adc6f
--- /dev/null
+++ b/647/CH1/EX1.10/Example1_10.sce
@@ -0,0 +1,23 @@
+clear;
+clc;
+
+// Example: 1.10
+// Page: 12
+
+// Solution
+
+printf("Example: 1.10 - Page: 12\n\n");
+
+//*****Data*****//
+m = 1200;// [kg]
+v1 = 10;// [km/h]
+v2 = 100;// [km/h]
+time = 1;// [min]
+//***************//
+
+v1 = 10*1000/3600;// [m/s]
+v2 = 100*1000/3600;// [m/s]
+W = (1/2)*m*(v2^2 - v1^2);// [J]
+time = time*60;// [s]
+P = W/time;// [W]
+printf("Power required is %.2f kW\n",P/1000);
+\ No newline at end of file
diff --git a/647/CH1/EX1.11/Example1_11.sce b/647/CH1/EX1.11/Example1_11.sce
new file mode 100755
index 000000000..e1bef5e98
--- /dev/null
+++ b/647/CH1/EX1.11/Example1_11.sce
@@ -0,0 +1,40 @@
+clear;
+clc;
+
+// Example: 1.11
+// Page: 13
+
+printf("Example: 1.11 - Page: 13\n\n");
+
+//*****Data*****//
+dia = 0.3;// [m]
+m = 100;// [kg]
+P_atm = 1.013*10^5;// [N/square m]
+g = 9.792;// [m/square s]
+//**************//
+
+Area = (%pi/4)*dia^2;// [square m]
+//Solution (a)(i)
+// Force exerted by the atmosphere:
+F_atm = P_atm*Area;// [N]
+// Force exerted by piston & metal block:
+F_mass = m*g;// [N]
+// Total force acting upon the gas:
+F = F_atm + F_mass;// [N]
+printf("Total Force eacting upon the gas is %.1f N\n",F);
+
+// Solution (a)(ii)
+Pressure = F/Area;// [N/square m]
+printf("Pressure exerted is %.3f kPa\n\n",Pressure/1000);
+
+// Solution (b)
+// The gas expands on application of heat, the volume of the gas goes on increasing and the piston moves upward.
+Z = 0.5;// [m]
+// Work done due to expansion of gas:
+W = F*Z;// [J]
+printf("Work due to expansion by the gas is %.3f kJ\n\n",W/1000);
+
+// Solution (c)
+// Change in potential energy of piston and weight after expansion process:
+Ep = m*g*Z;// [J]
+printf("Change in Potential Energy is %.1f J\n",Ep);
+\ No newline at end of file
diff --git a/647/CH1/EX1.12/Example1_12.sce b/647/CH1/EX1.12/Example1_12.sce
new file mode 100755
index 000000000..e9dcbc162
--- /dev/null
+++ b/647/CH1/EX1.12/Example1_12.sce
@@ -0,0 +1,15 @@
+clear;
+clc;
+
+// Example: 1.12
+// Page: 24
+
+printf("Example: 1.12 - Page: 24\n\n");
+
+// Solution
+
+// The relation is:
+// (C/5) = ((F - 32)/9)
+// For C = F
+C = - (32*5/4); // [degree Celsius]
+printf("The temperature which has the same value on both the centigrade and Fahrenheit scales is %d degree Celsius or %d degree Fahrenheit\n",C,C);
+\ No newline at end of file
diff --git a/647/CH1/EX1.13/Example1_13.sce b/647/CH1/EX1.13/Example1_13.sce
new file mode 100755
index 000000000..15431a639
--- /dev/null
+++ b/647/CH1/EX1.13/Example1_13.sce
@@ -0,0 +1,24 @@
+clear;
+clc;
+
+// Example: 1.13
+// Page: 24
+
+printf("Example: 1.13 - Page: 24\n\n");
+
+// Solution
+
+//*****Data*****//
+delta_T_C = 30;// [OC]
+//*************//
+
+// The relation between the Kelvin temperature scale and the Celsius temperature scale:
+// T(K) = T(OC) + 273.15
+// Here, the temperature rise is to be expressed in terms of K, but the difference in temperature will be the same in the Kelvin and Celsius scales of temperature:
+delta_T_K = delta_T_C;// [K]
+printf("The rise in temperature in the Kelvin scale is %d K\n",delta_T_K);
+// The emperical relationship between the Rankine and Kelvin scales is given by:
+delta_T_R = 1.8*delta_T_K;// [R]
+printf("The rise in temperature in the Rankine scale is %d R\n",delta_T_R);
+delta_T_F = delta_T_R;// [OF]
+printf("The rise in temperature in the Fahrenheit scale is %d OF\n",delta_T_F);
+\ No newline at end of file
diff --git a/647/CH1/EX1.2/Example1_2.sce b/647/CH1/EX1.2/Example1_2.sce
new file mode 100755
index 000000000..90116befd
--- /dev/null
+++ b/647/CH1/EX1.2/Example1_2.sce
@@ -0,0 +1,20 @@
+clear;
+clc;
+
+// Example: 1.2
+// Page: 5
+
+// Solution
+
+printf("Example: 1.2 - Page: 5\n\n");
+
+//*****Data*****//
+m1 = 1.5;// [mass of the body, kg]
+m2 = 6*10^(24);// [mass of the Earth, kg]
+G = 6.672*10^(-11);// [N.square m/square.kg]
+r = 6000*10^(3);// [m]
+//************//
+
+// According to Newton's universal law of gravity:
+F = G*m1*m2/r^2;// [N]
+printf("Gravitational force on the body is %.2f N\n",F);
+\ No newline at end of file
diff --git a/647/CH1/EX1.3/Example1_3.sce b/647/CH1/EX1.3/Example1_3.sce
new file mode 100755
index 000000000..e8d75be73
--- /dev/null
+++ b/647/CH1/EX1.3/Example1_3.sce
@@ -0,0 +1,20 @@
+clear;
+clc;
+
+// Example: 1.3
+// Page: 5
+
+// Solution
+
+printf("Example: 1.3 - Page: 5\n\n");
+
+//*****Data*****//
+r_Moon = 0.3;// [km]
+r_Earth = 1;// [km]
+m2 = 1;// [mass of body, kg]
+mMoon_By_mEarth = 0.013;// [kg/kg]
+//***************//
+
+// According to the Newton's universal law of gravitation:
+Fe_By_Fm = (1/mMoon_By_mEarth)*(r_Moon/r_Earth)^2;
+printf("Mass of 1 kg will weigh %.2f kg on moon\n",Fe_By_Fm);
+\ No newline at end of file
diff --git a/647/CH1/EX1.4/Example1_4.sce b/647/CH1/EX1.4/Example1_4.sce
new file mode 100755
index 000000000..78eacce40
--- /dev/null
+++ b/647/CH1/EX1.4/Example1_4.sce
@@ -0,0 +1,20 @@
+clear;
+clc;
+
+// Example: 1.4
+// Page: 6
+
+// Solution
+
+printf("Example: 1.4 - Page: 6\n\n");
+
+//*****Data*****//
+h = 40;// [cm]
+density = 14.02;// [g/cubic cm]
+g = 9.792;// [m/square s]
+//*************//
+
+P = h*density*g/1000;// [N/square cm]
+P = P*10;// [kPa]
+
+printf("The absolute pressure is %.3f kPa\n",P);
+\ No newline at end of file
diff --git a/647/CH1/EX1.5/Example1_5.sce b/647/CH1/EX1.5/Example1_5.sce
new file mode 100755
index 000000000..9061c5c6f
--- /dev/null
+++ b/647/CH1/EX1.5/Example1_5.sce
@@ -0,0 +1,20 @@
+clear;
+clc;
+
+// Example: 1.5
+// Page: 7
+
+// Solution
+
+printf("Example: 1.5 - Page: 7\n\n");
+
+//*****Data*****//
+Patm = 112;// [kPa]
+density = 1200;// [kg/cubic m]
+g = 9.81;// [m/sqaure s]
+h = 0.62;// [m]
+//**************//
+
+P = Patm + (density*g*h/1000);// [kPa]
+
+printf("The absolute pressure within the container is %.3f kPa\n",P);
+\ No newline at end of file
diff --git a/647/CH1/EX1.6/Example1_6.sce b/647/CH1/EX1.6/Example1_6.sce
new file mode 100755
index 000000000..805672ba3
--- /dev/null
+++ b/647/CH1/EX1.6/Example1_6.sce
@@ -0,0 +1,18 @@
+clear;
+clc;
+
+// Example: 1.6
+// Page: 9
+
+// Solution
+
+printf("Example: 1.6 - Page: 9\n\n");
+
+//*****Data*****//
+F = 150;// [N]
+Displacement = 10;// [m]
+//**************//
+
+W = F*Displacement;// [J]
+
+printf("Work done by the system is %d J\n",W);
+\ No newline at end of file
diff --git a/647/CH1/EX1.7/Example1_7.sce b/647/CH1/EX1.7/Example1_7.sce
new file mode 100755
index 000000000..402067119
--- /dev/null
+++ b/647/CH1/EX1.7/Example1_7.sce
@@ -0,0 +1,22 @@
+clear;
+clc;
+
+// Example: 1.7
+// Page: 9
+
+// Solution
+
+printf("Example: 1.7 - Page: 9\n\n");
+
+//*****Data*****//
+P = 560*10^3;// [Pa]
+Vinit = 3;// [cubic m]
+Vfinal = 5;// [cubic m]
+Wext = 210*10^3;// [J]
+//*************//
+
+W = P*(Vfinal - Vinit);// [J]
+// Again the system receives 210 kJ of work from the external agent.
+W = W - Wext;// [J]
+
+printf("Actual Work done by the system is %.1e J\n",W);
+\ No newline at end of file
diff --git a/647/CH1/EX1.8/Example1_8.sce b/647/CH1/EX1.8/Example1_8.sce
new file mode 100755
index 000000000..a4906635a
--- /dev/null
+++ b/647/CH1/EX1.8/Example1_8.sce
@@ -0,0 +1,19 @@
+clear;
+clc;
+
+// Example: 1.8
+// Page: 11
+
+// Solution
+
+printf("Example: 1.8 - Page: 11\n\n");
+
+//*****Data*****//
+g = 9.81;// [m/square s]
+Z = 100;//[m]
+//***************//
+
+// Basis: 1 kg of water
+m = 1;// [kg]
+Ep = m*g*Z;// [J]
+printf("Change in potential Energy is %d J\n",Ep)
+\ No newline at end of file
diff --git a/647/CH1/EX1.9/Example1_9.sce b/647/CH1/EX1.9/Example1_9.sce
new file mode 100755
index 000000000..4fe29b682
--- /dev/null
+++ b/647/CH1/EX1.9/Example1_9.sce
@@ -0,0 +1,28 @@
+clear;
+clc;
+
+// Example: 1.9
+// Page: 11
+
+// Solution
+
+printf("Example: 1.9 - Page: 11\n\n");
+
+//*****Data*****//
+m = 15; // [kg]
+g = 9.81;// [m/square s]
+V1 = 0;// [m/square s]
+Z1 = 12;// [m]
+Z2 = 0;// [m]
+//***************//
+
+// At initial condition, V1 = 0, so kinetic energy is zero.
+// At final condition, Z2 = 0, so potential energy is zero.
+// Ep1 + Ek1 = Ep2 + Ek2
+deff('[y] = f(V2)','y = ((1/2)*m*V1^2) + (m*g*Z1) - (((1/2)*m*V2^2) + (m*g*Z2))');
+V2 = fsolve(7,f);
+
+printf("The velocity of the metal block is %.2f m/s\n",V2);
+
+Ek2 = (1/2)*m*V2^2;// [J]
+printf("The final Kinetic Energy is %.1f J\n",Ek2);
+\ No newline at end of file