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Diffstat (limited to '632/CH9/EX9.21/example9_21.sce')
-rwxr-xr-x | 632/CH9/EX9.21/example9_21.sce | 25 |
1 files changed, 25 insertions, 0 deletions
diff --git a/632/CH9/EX9.21/example9_21.sce b/632/CH9/EX9.21/example9_21.sce new file mode 100755 index 000000000..ff9d7cb58 --- /dev/null +++ b/632/CH9/EX9.21/example9_21.sce @@ -0,0 +1,25 @@ +//clc()
+F = 1000;//kg/h
+xfwater = 0.7;
+xpwater = 0.2;
+xrwater = 0.20;
+xswater = 0.5;
+y1 = 0.0025;
+y2 = 0.05;
+//R - recycle, S - stream entering granulator, P - Product, G1 - air entering the drier, G2 - air leaving the drier,
+//takin overall, moisture free balance, F * xf = P * xp
+P = F * ( 1 - xfwater )/(1 - xpwater );
+// taking material balance at point where recycle strea joins the feed,
+// F = R + S
+//water balance, F*xfwater = R*xrwater + S*xswater,solving this we get,
+R = (-F*xfwater +F*xswater)/(xrwater - xswater);
+S = F + R;
+mleaving = P + R;//solid leaving the drier
+//dry air entering will there be in air leaving, therefore
+//G1 * ( 1 - y1 ) = G2 * ( 1 - y2 )
+// water balance over the drier gives, S*xswater+G1*y1=G2*y2+(P+R)*xpwater
+//from above 2 equations , we get
+G1 = ((mleaving*xpwater - S*xswater)/(y1 - y2*(1-y1)/(1-y2)));
+disp("kg/h",R,"(a)Amount of solid recycled = ")
+mdryair = G1 * (1 - y1);
+disp("kg/h",mdryair,"(b)circulation rate of air in the drier on dry basis = ")
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