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diff --git a/632/CH6/EX6.6/example6_6.jpeg b/632/CH6/EX6.6/example6_6.jpeg
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diff --git a/632/CH6/EX6.6/example6_6.sce b/632/CH6/EX6.6/example6_6.sce
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+//clc()
+Pswater1 = 6.08;//kPa 
+T1 = 313;//K
+//lnPs = 16.26205 - 3799.887/(T - 46.854)
+Tb1 =3799.887/(16.26205 - log(Pswater1)) + 46.854;
+disp("K",Tb1,"boiling point of water at 6.08kPa vapour pressure = ")
+Pswater2 = 39.33;//kPa
+T2 = 353;//K
+Tb2 =3799.887/(16.26205 - log(Pswater2)) + 46.854;
+disp("K",Tb2,"boiling point of water at 39.33 kPa vapour pressure = ")
+Tb = [Tb1 Tb2];
+T = [T1 T2];
+plot(T,Tb);
+xtitle('Equal pressure reference plot for sulphuric acid','Boiling point of solution,K','Boiling point of water, K');
+T3 = 333;//K
+//corresponding to T3 on x axis, on y we get
+Tb3 = 329;//K
+Pswater3 = exp(16.26205 - 3799.887/(Tb3 - 46.854));
+disp("kPa",Pswater3,"Vapour pressure of solution at 333K")