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diff --git a/632/CH12/EX12.5/example12_5.sce b/632/CH12/EX12.5/example12_5.sce
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+++ b/632/CH12/EX12.5/example12_5.sce
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+//clc()
+//C2H4(g) + H2O(g) = C2H5OH(g)
+//2CO2(g) + 3H2O(l) = C2H5OH(l) + 3O2(g)     H = 1366.91kJ  (A)
+Hc2h4 = -1410.99;//kJ/mol
+Hvap = 44.04;//kJ/mol
+Hc2h5oh = 42.37;//kJ/mol
+//C2H4(g) + 3H2O(l) = C2H5OH(l) + 3O2(g)     H = -1410.99kJ (B)
+//H2O(l) = H2O(g)                            H = 44.04kJ    (C)
+//C2H5OH(l) = C2H5OH(g)                      H = 42.37kJ    (D)
+//A + B + D - C gives the required reaction
+Ha = 1366.91;//kJ
+Hb = -1410.99;//kJ
+Hc = 44.04;//kJ
+Hd = 42.37;//kJ
+Hreac = Ha + Hb + Hd - Hc;
+disp("kJ",Hreac,"The standard heat of reaction = ")