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diff --git a/632/CH11/EX11.26/example11_26.sce b/632/CH11/EX11.26/example11_26.sce
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+//clc()
+Nwater = 0.8;//moles
+Nethanol = 0.2;//moles
+T = 323;//K
+Cwater = 4.18*10^3;//J/kgK
+Cethanol = 2.58*10^3;//J/kgK
+Hmixing1 = -758;//J/mol ( at 298K )
+Hmixing2 = -415;//J/mol ( at 323K )
+T1 = 298;//K
+T2 = 523;//K
+//step1 - 0.8 mol of water is cooled from 323 K to 298K
+H1 = Nwater * 18 * Cwater * ( T1 - T )/ 1000;
+//step2 - 0.2 mol ethanol cooled from 323K to 298K
+H2 = Nethanol * 46 * Cethanol * ( T1 - T )/1000;
+//step3 - 0.8 mol water and 0.2 mol ethanol are mixed together,
+H3 = Hmixing1;
+//step4 solution is heated to 323K, H4 = Cpm * (T - T1)
+//Hmixing2 = H1 + H2 + H3 + H4
+H4 = Hmixing2 - H1 - H2 - H3;
+Cpm = H4 / ( T - T1 );
+disp("J/molK",Cpm,"The mean heat capacity of a 20 percent solution = ")
+\ No newline at end of file