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+//clc()
+m = 1000;//kg/h ( basis  mass of 10% NaOH solution )
+Pfeed = 10;//%
+Ppro = 50;//(Percentage NaOH in product)
+//Taking NaOH balance,P being the weight of the product
+P = Pfeed * m / Ppro;
+//W be the weight of water evaporized
+W = m - P;
+//step1 - cooling 1000kg/h of 10% solution from 305K to 298K
+T1 = 305;//K
+T2 = 298;//K
+Cliq = 3.67;//kJ/kgK
+H1 = m*Cliq * (T2 - T1);
+//step2 - separation into pure components
+Hsolution = -42.85;//kJ/mol
+H2 = -Pfeed * m *1000 *Hsolution/ (40*100);
+//step3 - W kg water is converted to water vapour
+Hvap = 2442.5;//kJ/kg
+H3 = W * Hvap;
+//step4 - water vapour at 298K is heated to 373.15K
+Cvap = 1.884;//kJ/kgK
+T3 = 373.15;//K
+H4 = W * Cvap * ( T3 - T2 );
+//step5 - formation of 200kg of 50% NaOH solution at 298K
+Hsolu = -25.89;//kJ/mol
+H5 = Pfeed * m *1000 *Hsolu/ (40*100);
+//step6 - Heating the solution from 298K to 380K
+Csolu = 3.34;//kJ/kg
+T4 = 380;//K
+H6 = P * Csolu * (T4 - T2);
+Htotal = H1 + H2 + H3 + H4 + H5 + H6;
+disp("kJ",Htotal,"The enthalpy change accompanying the complete process = ")
+\ No newline at end of file