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Diffstat (limited to '632/CH10/EX10.20/example10_20.sce')
-rwxr-xr-x | 632/CH10/EX10.20/example10_20.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/632/CH10/EX10.20/example10_20.sce b/632/CH10/EX10.20/example10_20.sce new file mode 100755 index 000000000..24e9e5a94 --- /dev/null +++ b/632/CH10/EX10.20/example10_20.sce @@ -0,0 +1,22 @@ +//clc()
+m = 100;//kg ( basis - sucrose solution as fresh feed )
+//R - recycle reactor exit, let x be the weight fraction of sucrose and y be the weight fracton of inversion sugar in the recycle stream, for combined stream fraction of Glucose + fructose = 0.04
+//z be the weight fraction of sucrose in the combined stream entering the reactor
+Psfeed = 25;//% percent sucrose in fresh feed
+//sucrose balance gives, 25 + R*x = (100+R)* z (A)
+//Glucose + fructose balance, R * y = (100 + R )*0.04 (B)
+Sucrosecon = 71.7;//% sucrose consumed
+//sucrose balance around the reactor,(100+R)z=0.717*(100+R)z+(100+R)x (C)
+//From (C) , x = 0.283*z (D)
+//Amount converted to Glucose + fructose = 0.717 ( 100 + R )* z
+// = 0.717 ( 100 + R )* z * 360.192 / 342.176 kg
+//Glucose and fructose balance around the reactor,
+//(100+R)*0.04 + 0.717(100+R)*z*360.192/342.176 = (100+R)*y (E)
+//Solving (E), y = 0.04 + 0.7548*z (F)
+//Solving, (A), (B), (C) and (F)
+x = 0.06;
+y = 0.2;
+z = 0.212;
+R = 25;
+disp("kg",R,"(a)Recycle flow = ")
+disp("%",y*100,"(b)Combined concentration of Glucose and Fructose in the recycle stream = ")
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