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diff --git a/611/CH9/EX9.1/Chap9_Ex1_R1.sce b/611/CH9/EX9.1/Chap9_Ex1_R1.sce new file mode 100755 index 000000000..2522476e1 --- /dev/null +++ b/611/CH9/EX9.1/Chap9_Ex1_R1.sce @@ -0,0 +1,28 @@ +// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India.
+
+//Chapter-9,Example 1,Page 313
+//Title: Partial molar volume
+//================================================================================================================
+clear
+clc
+
+//INPUT
+per_ethanol=60;//mole percent of ethanol in a ethanol-water system
+per_water=40;//mole percent of water in a ethanol-water system
+v1=57.5*10^-6;//partial molar volume of ethanol in the ethanol-water system in m^3
+rho=849.4;//density of the mixture in kg/m^3
+M_ethanol=46*10^-3;//molar mass of ethanol in kg/mol
+M_water=18*10^-3;//molar mass of ethanol in kg/mol
+
+//CALCULATION
+X1=per_ethanol/100;//calculation of the mole fraction of ethanol (no unit)
+X2=per_water/100;//calculation of the mole fraction of water (no unit)
+M=(X1*M_ethanol)+(X2*M_water);//calculation of the molar mass of the ethanol-water mixture in kg/mol
+v=M/rho;//calculation of the molar volume of the mixture in m^3/mol
+v2=(v-(X1*v1))/(X2);//calculation of the partial molar volume of water using Eq.(9.10) in m^3/mol
+
+//OUTPUT
+mprintf("\n The partial molar volume of water = %f m^3/mol\n",v2);
+
+//===============================================END OF PROGRAM===================================================
+
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