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diff --git a/611/CH5/EX5.4/Chap5_Ex4_R1.sce b/611/CH5/EX5.4/Chap5_Ex4_R1.sce new file mode 100755 index 000000000..789da876f --- /dev/null +++ b/611/CH5/EX5.4/Chap5_Ex4_R1.sce @@ -0,0 +1,24 @@ +// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India.
+
+//Chapter-5,Example 4,Page 166
+//Title: Minimum work and maximum possible COP
+//================================================================================================================
+clear
+clc
+
+//INPUT
+T_L=4.25;//normal boiling point of helium in K
+Q_L=0.083;//latent heat of vaporization of helium in kJ/mol
+n=1;//amount of liquid helium to be produced in kmol
+T_amb=42;//ambient temperature in summer in degree celsius
+
+//CALCULATION
+T_H=T_amb+273.15;//conversion of temperature in K
+COP=(T_L)/(T_H-T_L);//calculation of COP of the refrigerator using Eq.(5.20)(no unit)
+W=(Q_L)/COP;//calculation of work to be done on the refrigerator unit using Eq.(5.20) in kJ
+
+//OUTPUT
+mprintf("\n The maximum possible COP of the unit=%0.4f \n",COP);
+mprintf("\n The minimum amount of work to be done on the refrigerating unit=%f kJ \n",W);
+
+//===============================================END OF PROGRAM===================================================
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