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+//Problem 40.23: The airgap of a moving coil instrument is 2.0 mm long and has a cross-sectional area of 500 mm2. If the flux density is 50 mT, determine the total energy stored in the magnetic field of the airgap.
+
+//initializing the variables:
+B = 0.05; // in Tesla
+A = 500E-6; // in m2
+l = 0.002; // in m
+u0 = 4*%pi*1E-7; 
+
+//calculation:
+//energy stored
+W = (B^2)/(2*u0)
+//Volume of airgap
+v = A*l
+//energy stored in airgap
+W = W*v
+
+printf("\n\n Result \n\n")
+printf("\nenergy stored in the airgap is %.2E J",W)
+\ No newline at end of file