summaryrefslogtreecommitdiff
path: root/608/CH40/EX40.07/40_07.sce
diff options
context:
space:
mode:
Diffstat (limited to '608/CH40/EX40.07/40_07.sce')
-rwxr-xr-x608/CH40/EX40.07/40_07.sce28
1 files changed, 28 insertions, 0 deletions
diff --git a/608/CH40/EX40.07/40_07.sce b/608/CH40/EX40.07/40_07.sce
new file mode 100755
index 000000000..eb6adfe5a
--- /dev/null
+++ b/608/CH40/EX40.07/40_07.sce
@@ -0,0 +1,28 @@
+//Problem 40.07: A concentric cable has a core diameter of 25 mm and an inside sheath diameter of 80 mm. The relative permittivity of the dielectric is 2.5, the loss angle is 3.5 x 10-3 rad and the working voltage is 132 kV at 50 Hz frequency. Determine for a 1 km length of the cable (a) the capacitance, (b) the charging current and (c) the power loss.
+
+//initializing the variables:
+e0 = 8.85E-12;
+er = 2.5;
+di = 0.08; // in m
+d0 = 0.025; // in m
+r = 1000; // in m
+V = 132000; // in Volts
+f = 50; // in Hz
+del = 3.5E-3; // rad.
+
+//calculation:
+//core radius, a
+a = d0/2
+//internal sheath radius,
+b = di/2
+//capacitance
+C = 2*%pi*e0*er*1E3/(log(b/a))
+//Charging current
+I = V*2*%pi*f*C
+//power loss
+P = (2*%pi*f*C*tan(del))*V^2
+
+printf("\n\n Result \n\n")
+printf("\n (a)capacitance for a 1 km length is %.2E F",C)
+printf("\n (b)the charging current %.2E A/km",I)
+printf("\n (c)power loss %.0f W",P) \ No newline at end of file