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Diffstat (limited to '608/CH35/EX35.05/35_05.sce')
-rwxr-xr-x | 608/CH35/EX35.05/35_05.sce | 23 |
1 files changed, 23 insertions, 0 deletions
diff --git a/608/CH35/EX35.05/35_05.sce b/608/CH35/EX35.05/35_05.sce new file mode 100755 index 000000000..b40f34f2d --- /dev/null +++ b/608/CH35/EX35.05/35_05.sce @@ -0,0 +1,23 @@ +//Problem 35.05: Determine the value of the load resistance R shown in Figure 35.5 that gives maximum power dissipation and calculate the value of this power.
+
+//initializing the variables:
+V = 20; // in volts
+R1 = 5; // in ohm
+R2 = 15; // in ohm
+
+//calculation:
+//R is removed from the network as shown in Figure 35.6
+//P.d. across AB, E
+E = (R2/(R1 + R2))*V
+//Impedance ‘looking-in’ at terminals AB with the source removed is given by
+r = R1*R2/(R1 + R2)
+//The equivalent Th´evenin circuit supplying terminals AB is shown in Figure 35.7. From condition (2), for maximum power transfer
+R = r
+//Current I flowing in the load is given by
+I = E/(R + r)
+//maximum power transferred,
+P = R*I^2
+
+printf("\n\n Result \n\n")
+printf("\n (a)maximum power transfer occurs when R is %.2f ohm",R)
+printf("\n (b) maximum power delivered is %.0f W",P)
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