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Diffstat (limited to '608/CH33/EX33.03/33_03.sce')
-rwxr-xr-x | 608/CH33/EX33.03/33_03.sce | 30 |
1 files changed, 30 insertions, 0 deletions
diff --git a/608/CH33/EX33.03/33_03.sce b/608/CH33/EX33.03/33_03.sce new file mode 100755 index 000000000..e0004c896 --- /dev/null +++ b/608/CH33/EX33.03/33_03.sce @@ -0,0 +1,30 @@ +//Problem 33.03: Use Th´evenin’s theorem to determine the power dissipated in the 48 ohm resistor of the network shown in Figure 33.19
+
+//initializing the variables:
+rv = 50; // in volts
+thetav = 0; // in degrees
+R1 = -1*%i*400; // in ohm
+R2 = 300; // in ohm
+R3 = %i*144; // in ohm
+R4 = 48; // in ohm
+
+//calculation:
+//voltage
+V = rv*cos(thetav*%pi/180) + %i*rv*sin(thetav*%pi/180)
+//The R3 and R4 impedance is initially removed from the network as shown in Figure 33.20.
+//From Figure 33.20,
+//current, I
+i = V/(R1 + R2)
+//the open circuit e.m.f. E
+E = i*R2
+//When the V is removed from the circuit, the impedance, z, ‘looking in’ at the break is given by
+z = R1*R2/(R1 + R2)
+//The Th´evenin equivalent circuit is shown in Figure 33.21 connected to R# and R4,
+//Hence current
+I = E/(R4 + R3 + z)
+Imag = (real(I)^2 + imag(I)^2)^0.5
+//the power dissipated in the 48 ohm resistor
+Pr48 = R4*Imag^2
+
+printf("\n\n Result \n\n")
+printf("\n the power dissipated in the 48 ohm resistor is %.2f W",Pr48)
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