diff options
Diffstat (limited to '608/CH21/EX21.28')
-rwxr-xr-x | 608/CH21/EX21.28/21_28.sce | 52 |
1 files changed, 26 insertions, 26 deletions
diff --git a/608/CH21/EX21.28/21_28.sce b/608/CH21/EX21.28/21_28.sce index d0bef77dc..08fab7bec 100755 --- a/608/CH21/EX21.28/21_28.sce +++ b/608/CH21/EX21.28/21_28.sce @@ -1,27 +1,27 @@ -//Problem 21.28: A 500 V shunt motor runs at its normal speed of 10 rev/s when the armature current is 120 A. The armature resistance is 0.2 ohm. (a) Determine the speed when the current is 60 A and a resistance of 0.5 ohm is connected in series with the armature, the shunt field remaining constant. (b) Determine the speed when the current is 60 A and the shunt field is reduced to 80% of its normal value by increasin resistance in the field circuit.
-
-//initializing the variables:
-Ia1 = 120; // in A
-Ia2 = 60; // in A
-Ra = 0.2; // in ohm
-n1 = 10; // in rev/sec
-R = 0.5; // in ohm
-x = 0.8;
-V = 500; // in Volts
-
-//calculation:
-//back e.m.f. at Ia1
-E1 = V - Ia1*Ra
-//at Ia2
-E2 = V - Ia2*(Ra + R)
-//E1/E2 = Phi1*n1/Phi2*n2
-Phi2 = Phi1
-n2 = Phi1*n1*E2/(Phi2*E1)
-//Back e.m.f. when Ia2
-E3 = V - Ia2*Ra
-Phi3 = x*Phi1
-n3 = Phi1*n1*E3/(Phi3*E1)
-
-printf("\n\n Result \n\n")
-printf("\n (a)speed n2 is %.2f rev/sec", n2)
+//Problem 21.28: A 500 V shunt motor runs at its normal speed of 10 rev/s when the armature current is 120 A. The armature resistance is 0.2 ohm. (a) Determine the speed when the current is 60 A and a resistance of 0.5 ohm is connected in series with the armature, the shunt field remaining constant. (b) Determine the speed when the current is 60 A and the shunt field is reduced to 80% of its normal value by increasin resistance in the field circuit. + +//initializing the variables: +Ia1 = 120; // in A +Ia2 = 60; // in A +Ra = 0.2; // in ohm +n1 = 10; // in rev/sec +R = 0.5; // in ohm +x = 0.8; +V = 500; // in Volts + +//calculation: +//back e.m.f. at Ia1 +E1 = V - Ia1*Ra +//at Ia2 +E2 = V - Ia2*(Ra + R) +//E1/E2 = Phi1*n1/Phi2*n2 +//Phi2 = Phi1 +n2 = n1*E2/(E1) +//Back e.m.f. when Ia2 +E3 = V - Ia2*Ra +//Phi3 = x*Phi1 +n3 = n1*E3/(0.8*E1) + +printf("\n\n Result \n\n") +printf("\n (a)speed n2 is %.2f rev/sec", n2) printf("\n (b)speed n3 is %.2f rev/sec", n3)
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