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-rwxr-xr-x608/CH21/EX21.28/21_28.sce52
1 files changed, 26 insertions, 26 deletions
diff --git a/608/CH21/EX21.28/21_28.sce b/608/CH21/EX21.28/21_28.sce
index d0bef77dc..08fab7bec 100755
--- a/608/CH21/EX21.28/21_28.sce
+++ b/608/CH21/EX21.28/21_28.sce
@@ -1,27 +1,27 @@
-//Problem 21.28: A 500 V shunt motor runs at its normal speed of 10 rev/s when the armature current is 120 A. The armature resistance is 0.2 ohm. (a) Determine the speed when the current is 60 A and a resistance of 0.5 ohm is connected in series with the armature, the shunt field remaining constant. (b) Determine the speed when the current is 60 A and the shunt field is reduced to 80% of its normal value by increasin resistance in the field circuit.
-
-//initializing the variables:
-Ia1 = 120; // in A
-Ia2 = 60; // in A
-Ra = 0.2; // in ohm
-n1 = 10; // in rev/sec
-R = 0.5; // in ohm
-x = 0.8;
-V = 500; // in Volts
-
-//calculation:
-//back e.m.f. at Ia1
-E1 = V - Ia1*Ra
-//at Ia2
-E2 = V - Ia2*(Ra + R)
-//E1/E2 = Phi1*n1/Phi2*n2
-Phi2 = Phi1
-n2 = Phi1*n1*E2/(Phi2*E1)
-//Back e.m.f. when Ia2
-E3 = V - Ia2*Ra
-Phi3 = x*Phi1
-n3 = Phi1*n1*E3/(Phi3*E1)
-
-printf("\n\n Result \n\n")
-printf("\n (a)speed n2 is %.2f rev/sec", n2)
+//Problem 21.28: A 500 V shunt motor runs at its normal speed of 10 rev/s when the armature current is 120 A. The armature resistance is 0.2 ohm. (a) Determine the speed when the current is 60 A and a resistance of 0.5 ohm is connected in series with the armature, the shunt field remaining constant. (b) Determine the speed when the current is 60 A and the shunt field is reduced to 80% of its normal value by increasin resistance in the field circuit.
+
+//initializing the variables:
+Ia1 = 120; // in A
+Ia2 = 60; // in A
+Ra = 0.2; // in ohm
+n1 = 10; // in rev/sec
+R = 0.5; // in ohm
+x = 0.8;
+V = 500; // in Volts
+
+//calculation:
+//back e.m.f. at Ia1
+E1 = V - Ia1*Ra
+//at Ia2
+E2 = V - Ia2*(Ra + R)
+//E1/E2 = Phi1*n1/Phi2*n2
+//Phi2 = Phi1
+n2 = n1*E2/(E1)
+//Back e.m.f. when Ia2
+E3 = V - Ia2*Ra
+//Phi3 = x*Phi1
+n3 = n1*E3/(0.8*E1)
+
+printf("\n\n Result \n\n")
+printf("\n (a)speed n2 is %.2f rev/sec", n2)
printf("\n (b)speed n3 is %.2f rev/sec", n3) \ No newline at end of file