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+//Problem 21.25: A 250 V series motor draws a current of 40 A. The armature resistance is 0.15 ohm and the field resistance is 0.05ohm . Determine the maximum efficiency of the motor.
+
+//initializing the variables:
+I = 40; // in Amperes
+Rf = 0.05; // in ohms
+Ra = 0.15; // in ohm
+V = 250; // in Volts
+
+//calculation:
+//However for a series motor, If = 0 and the Ia*Ia*Ra loss needs to be I*I*(Ra + Rf)
+//For maximum efficiency I*I*(Ra + Rf) = C
+//Efficiency =((V*I -2*Ia*Ia*Ra)/(V*I))*100%
+eff = ((V*I - (2*I*I*(Ra + Rf)))/(V*I))*100 // in percent
+
+printf("\n\n Result \n\n")
+printf("\n efficiency is %.1f",eff)
+\ No newline at end of file