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+//Problem 20.28: A current transformer has a single turn on the primary winding and a secondary winding of 60 turns. The secondary winding is connected to an ammeter with a resistance of 0.15 ohm. The resistance of the secondary winding is 0.25 ohm. If the current in the primary winding is 300 A, determine (a) the reading on the ammeter, (b) the potential difference across the ammeter and (c) the total load (in VA) on the secondary.
+
+//initializing the variables:
+N1 = 1; // prim turns
+N2 = 60; // sec turns
+I1 = 300; // in amperes
+Ra = 0.15; // in ohms
+R2 = 0.25; // in ohms
+
+//calculation:
+//Reading on the ammeter,
+I2 = I1*(N1/N2)
+//P.d. across the ammeter = I2*RA, where RA is the ammeter resistance
+pd = I2*Ra
+//Total resistance of secondary circuit
+Rt = Ra + R2
+//Induced e.m.f. in secondary
+V2 = I2*Rt
+//Total load on secondary
+S = V2*I2
+
+printf("\n\n Result \n\n")
+printf("\n (a)the reading on the ammeter is %.0f A ",I2)
+printf("\n (b)potential difference across the ammeter is %.2f V ",pd)
+printf("\n (c)total load (in VA) on the secondary is %.0f VA ",S)
+\ No newline at end of file