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+// data given in question
+// diameter of dish (m)
+d=30;
+//frequency of radiation (Hz)
+f=4*10^9;
+// speed of light(m/s)
+c=3*10^8;
+// efficiency of aperture
+e=0.6;
+//data print
+printf("\nd=30 m\tf=4 GHz\te=0.6\n")
+// equation and result
+printf("\nresult:-")
+wavelength=c/f
+printf("\nwavelength of radiating signal=c/f= %.3f m",wavelength)
+A=%pi*d^2/4
+printf("\narea of aperture A=pi*d^2/4=%.4f m^2",A)
+G=4*%pi*A*e/wavelength^2
+
+printf("\nantenna gain G=4*pi*A*e/wavelength^2 =%.3f",G)
+printf("=%.0f dB",10*log10(G))
+BW=65*wavelength/d
+printf("\nhalf power beam width BW=65*wavelength/d=%.4f degree",BW)
+