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+
+clear;
+clc;
+printf("\t Example 6.15\n");
+
+t1=20; //ambient air temperature
+t2=70; //exhaust air temperature
+r1=150; //evaporation of water
+r2=.25; //outlet solid moisture content
+t3=15; //inlet solid temperature
+t4=65; //outlet solid temperature
+p=5; //power demand in KW
+h=18; //heat loss in kj
+
+h1=1; //mean specific heat of dry air in kj/kg*K
+h2=1.25; //mean specific heat of dry material in kj/kg*K
+h3=4.18; //mean specific heat of moisture in kj/kg*K
+e=2626; //enthalpy of saturated water vapour in kj/kg
+
+ //basis is 1hr
+a1=r1*h3*(t4-t3); //heat required for heating 150 kg of water from 15 to 65
+a2=r1*e; //heat required for 150 kg water evaporation
+a3=2000*h1*(t2-t1); //heat required for heating air from 20 to 70
+a4=r2*h3*(t4-t3); //heat required for heating moisture from 15 to 65
+a5=120*h2*(t4-t3); //heat required for heating dry solid from 15 to 65
+hlost=h*3600; //heat lost in kj
+total=(a2+a3+a4+a5+hlost)/3600; //total heat lost
+printf("\n :%f kW of heat required for 2000kg/hr of dry air",total);
+ans1=a2+a1; //heat needed for evaporation
+printf("\n heat needed fro evaporation is :%f",ans1/3600);
+ans2=(ans1/3600)/total; //fraction of this heat needed for evaporation
+printf("\n fraction of this heat needed for evaporation:%f",ans2);
+
+
+//end \ No newline at end of file