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+clear;
+clc;
+
+//Example2.7[Heat Flux boundary Condition]
+//Given:-
+Q=800;//Heat transfer rate[W]
+D=0.2;//Diameter of pan[m]
+L=0.003;//Thickness of pan[m]
+T_in=110;//T(L) Temperature of the inner surface of the pan[degree Celcius]
+neta=0.9;//Percent of total heat transferred to the pan
+//Solution;-
+//The inner and outer surfaces of the bottom section of the pan can be represented by x=0 and x=L,respectively. During steady operation the temperature will depend on x only and thus T=T(x).
+//Solution:-
+actual_Q=neta*Q;//90 percent of the 800W is transferred to the pan at that surface
+A=%pi*(D^2)/4;//Bottom Surface Area[m^2]
+disp("-k*dT(0)/dx=q_")
+q_=actual_Q/(1000*A);//[kW/m^2]
+//The boundary condition on this surface can be expressed as
+disp("degree Celcius",T_in,"T(L)=")
+disp("m",L,"where L=")