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Diffstat (limited to '572/CH8/EX8.4/c8_4.sce')
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diff --git a/572/CH8/EX8.4/c8_4.sce b/572/CH8/EX8.4/c8_4.sce new file mode 100755 index 000000000..172e3ded4 --- /dev/null +++ b/572/CH8/EX8.4/c8_4.sce @@ -0,0 +1,34 @@ +//(8.4) Reconsider the reheat cycle of Example 8.3, but include in the analysis that each turbine stage has the same isentropic efficiency. (a) If etat = 85%, determine the thermal efficiency. (b) Plot the thermal efficiency versus turbine stage efficiency ranging from 85 to 100%.
+
+
+//solution
+
+//part (a)
+etat = .85 //given efficiency
+//From the solution to Example 8.3, the following specific enthalpy values are known, in kJ/kg
+h1 = 3348.4
+h2s = 2741.8
+h3 = 3353.3
+h4s = 2428.5
+h5 = 173.88
+h6 = 181.94
+
+h2 = h1 - etat*(h1 - h2s) //The specific enthalpy at the exit of the first-stage turbine in kj/kg
+h4 = h3 - etat*(h3-h4s) //The specific enthalpy at the exit of the second-stage turbine in kj/kg
+
+eta = ((h1-h2)+(h3-h4)-(h6-h5))/((h1-h6)+(h3-h2))
+printf('the thermal efficiency is: %f',eta)
+
+
+//part (b)
+x = linspace(.85,1,50);
+for i = 1: 50
+ h2(1,i) = h1 - x(1,i)*(h1 - h2s) //The specific enthalpy at the exit of the first-stage turbine in kj/kg
+h4(1,i) = h3 - x(1,i)*(h3-h4s) //The specific enthalpy at the exit of the second-stage turbine in kj/kg
+end
+
+for i = 1:50
+ y(1,i) = ((h1-h2(1,i))+(h3-h4(1,i))-(h6-h5))/((h1-h6)+(h3-h2(1,i)))
+end
+plot2d(x,y)
+xtitle("","isentropic turbine efficiency","cycle thermal efficiency")
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