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diff --git a/572/CH12/EX12.15/c12_15.sce b/572/CH12/EX12.15/c12_15.sce new file mode 100755 index 000000000..f36fb65a7 --- /dev/null +++ b/572/CH12/EX12.15/c12_15.sce @@ -0,0 +1,50 @@ +//(12.15) Water exiting the condenser of a power plant at 38C enters a cooling tower with a mass flow rate of 4.5 X 107 kg/h. A stream of cooled water is returned to the condenser from a cooling tower with a temperature of 30C and the same flow rate. Makeup water is added in a separate stream at 20C. Atmospheric air enters the cooling tower at 25C and 35% relative humidity. Moist air exits the tower at 35C and 90% relative humidity. Determine the mass flow rates of the dry air and the makeup water, in kg/h. The cooling tower operates at steady state. Heat transfer with the surroundings and the fan power can each be neglected, as can changes in kinetic and potential energy. The pressure remains constant throughout at 1 atm.
+
+
+//solution
+
+//variable initialization
+T1 = 38 //in degree celcius
+m1dot = 4.5e7 //in kg/h
+T2 = 30 //in degree celcius
+m2dot = 4.5e7 //in kg/h
+T3 = 25 //in degree celcius
+psi3 = .35
+T4 = 35 //in degree celcius
+psi4 = .9
+T5 = 20 //in degree celcius
+
+//analysis
+//The humidity ratios omega3 and omega4 can be determined using the partial pressure of the water vapor obtained with the respective relative humidity
+omega3 =.00688
+omega4 = .0327
+//from tables A-2 and A-22
+hf1 = 159.21
+hf2 = 125.79
+ha4 = 308.2
+ha3 = 298.2
+hg4 = 2565.3
+hg3 = 2547.2
+hf5 = 83.96
+
+madot = [m1dot*(hf1-hf2)]/[ha4-ha3+omega4*hg4-omega3*hg3-(omega4-omega3)*hf5] //in kg/h
+m5dot = madot*(omega4-omega3) //in kg/h
+printf('the mass flow rate of dry air in kg/h is: %e',madot)
+printf('\nthe mass flow rate of makeup water in kg/h is: %e',m5dot)
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