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Diffstat (limited to '572/CH12/EX12.10/c12_10.sce')
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diff --git a/572/CH12/EX12.10/c12_10.sce b/572/CH12/EX12.10/c12_10.sce new file mode 100755 index 000000000..56f685c64 --- /dev/null +++ b/572/CH12/EX12.10/c12_10.sce @@ -0,0 +1,47 @@ +//(12.10) Moist air enters a duct at 10C, 80% relative humidity, and a volumetric flow rate of 150 m3/min. The mixture is heated as it flows through the duct and exits at 30C. No moisture is added or removed, and the mixture pressure remains approximately constant at 1 bar. For steady-state operation, determine (a) the rate of heat transfer, in kJ/min, and (b) the relative humidity at the exit. Changes in kinetic and potential energy can be ignored.
+
+//solution
+
+//variable initialization
+AV1 = 150 //entry volumetric flow rate in m^3/min
+T1 = 10 //entry temperature in degree celcius
+psi1 = .8
+T2 = 30 //exit temperature in degree celcius
+p = 1 //in bar
+
+//part(a)
+Rbar = 8314 //universal gas constant
+Ma = 28.97 //molar mass of air
+//The specific enthalpies of the dry air are obtained from Table A-22 at the inlet and exit temperatures T1 and T2, respectively:
+ha1 = 283.1 //in kj/kg
+ha2 = 303.2 //in kj/kg
+//The specific enthalpies of the water vapor are found using hv hg and data from Table A-2 at T1 and T2, respectively:
+hv1 = 2519.8 //in kj/kg
+hv2 = 2556.3 //in kj/kg
+//from table A-2
+pg1 = .01228 //in bar
+pv1 = psi1*pg1 //the partial pressure of the water vapor in bar
+pa1 = p-pv1
+va1 = (Rbar/Ma)*(T1+273)/(pa1*10^5) //specific volume of the dry air in m^3/kg
+
+madot = AV1/va1 //mass flow rate of the dry air in kg/min
+
+omega = .622*(pv1/(p-pv1)) //humidity ratio
+
+Qcvdot = madot*[(ha2-ha1)+omega*(hv2-hv1)] //in kj/min
+printf('rate of heat transfer, in kJ/min is: %f',Qcvdot)
+
+//part(b)
+//from Table A-2 at 30C
+pg2 = .04246 //in bar
+pv2 = pv1
+psi2 = pv2/pg2 //relative humidity at the exit
+printf('\n\nthe relative humidity at the exit is: %f',psi2)
+
+
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+
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