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+clear;
+clc;
+printf("\n Example 1.6");
+//To calculate mass flow of the dust emitted
+mass_1=10;//in percentage in the size range of 0-5um
+mass_2=15;//in percentage in the size range of 5-10um
+mass_3=35;//in percentage in the size range of 10-20um
+mass_4=20;//in percentage in the size range of 20-40um
+mass_5=10;//in percentage in the size range of 40-80um
+mass_6=10;//in percentage in the size range of 80-160um
+efficiecny_1=20;//in percentage in the size range of 0-5um
+efficiency_2=40;//in percentage in the size range of 5-10um
+efficiency_3=80;//in percentage in the size range of 10-20um
+efficiency_4=90;//in percentage in the size range of 20-40um
+efficiency_5=95;//in percentage in the size range of 40-80um
+efficiency_6=100;//in percentage in the size range of 80-160um
+dust_burden=18;//in g/m^3 at the entrance
+//taking 1m^3 as the basis of calculation
+total_mass_retained=18*(0.1*0.20+0.15*0.40+0.35*0.80+0.2*0.9+0.1*0.95+0.1*1);
+printf("\ntotal mass retained =%fg",total_mass_retained);
+total_efficiency=(total_mass_retained/18)*100;
+printf("\ntotal efficiency is =%f",total_efficiency);
+total_mass_emitted=18-total_mass_retained;
+printf("total mass emitted is:%fg",total_mass_emitted);
+t=18*(0.1*0.80+0.15*0.60+0.35*0.20);
+printf("\ntotal mass emitted less than 20um is %fg",t);
+e=t*100/total_mass_emitted;
+printf("\nThe efficiency of particles emitted is %f",e);
+//gas flow is 0.3m^3/sec
+f=0.3*total_mass_emitted;
+printf("\nmass flow rate is:%fkg/sec",f);
+
+
+
+