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+clear;
+clc;
+
+//Caption:To find Q point
+//Given Data
+Vcc=22.5//in V
+Rc=5.6;//in K
+Re=1;//in K
+R2=10;//in K
+R1=90;//in K
+B=55;//beta
+
+
+V=(R2*Vcc)/(R2+R1);//Thevenin Equivallent Voltage
+Rb=(R2*R1)/(R2+R1);//Thevenin Equivallent Resistance
+disp('Volts',V,'The equivallent Vbb =');
+disp('ohm',Rb,'The equivallent Rb is');
+
+//For base current large compared to reverse saturation current ie Ib>>Ico it follows that Ic=B*Ib
+
+//Applying KVL to the base circuit
+//0.65-2.25+Ic+10*Ib=0
+disp('As B=55 we have Ic=55*Ib');
+
+//We have   -1.60+Ic+(10/55)*Ic=0
+Ic=1.60/(65/55);
+Ib=Ic/55;
+disp('milli amp',Ic,'Ic=');
+disp('micro amp',Ib,'Ib=');
+
+//Applying KVL to the collector circuit yields
+//-22.5+6.6*Ic+Ib+Vce
+
+Vce = 22.5-(6.6*1.36)-0.025;
+disp('Volts',Vce,'Vce=');
+
+//end
+\ No newline at end of file