9 files changed, 219 insertions, 0 deletions
diff --git a/506/CH10/EX10.1.a/Example10_1a.sce b/506/CH10/EX10.1.a/Example10_1a.sce
new file mode 100755
index 000000000..ae264791d
--- /dev/null
+++ b/506/CH10/EX10.1.a/Example10_1a.sce
@@ -0,0 +1,17 @@
+clear;
+clc;
+
+//Caption: Pinch off V and channel half width of silicon FET
+
+//Given Values
+a=3*(10^-4);//in cm
+Nd=10^15;//in electrons/cm^3
+q=1.6*(10^-19)//in C
+eo=8.85*(10^-12);//Permittivity of free space
+e=12*eo;//Relative Permittivity
+
+Vp=(q*Nd*a*a*10^6*10^-4)/(2*e);//in V
+//a is in cm so 10^-4 is multiplied and Nd is in electrons/cm^3 so 10^6 is multiplied
+disp('V',Vp,'Pinch off Voltage =');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.1.b/Example10_1b.sce b/506/CH10/EX10.1.b/Example10_1b.sce
new file mode 100755
index 000000000..2972ceb14
--- /dev/null
+++ b/506/CH10/EX10.1.b/Example10_1b.sce
@@ -0,0 +1,21 @@
+clear;
+clc;
+
+//Caption: Pinch off V and channel half width of silicon FET
+
+//Given Values
+a=3*(10^-4);//in m
+Nd=10^15;//in electrons/m^3
+q=1.6*(10^-19)//in C
+eo=8.85*(10^-12);//Permittivity of free space
+e=12*eo;//Relative Permittivity
+
+Vp=(q*Nd*a*a*10^6*10^-4)/(2*e);//in V
+//a is in cm so 10^-4 is multiplied and Nd is in electrons/cm^3 so 10^6 is multiplied
+Vgs= Vp/2;
+
+b=a*(1-((Vgs/Vp)^(0.5)));//in cm
+
+disp('cm',b,'Channel Half Width = ');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.2.a/Example10_2a.sce b/506/CH10/EX10.2.a/Example10_2a.sce
new file mode 100755
index 000000000..40fb22665
--- /dev/null
+++ b/506/CH10/EX10.2.a/Example10_2a.sce
@@ -0,0 +1,19 @@
+clear;
+clc;
+
+//Caption:amplifier using n channel FET
+
+//Given Data
+
+Vp=-2;//in V
+Idss=1.65;//in mA
+//it is desired to bias the circut at Id=0.8mA
+Ids=0.8;//in mA
+Vdd=24;//in V
+//Assumption: rd>Rd
+
+Vgs=Vp*(1-(Ids/Idss)^0.5);//in V
+disp('V',Vgs,'Vgs=');
+
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.2.b/Example10_2b.sce b/506/CH10/EX10.2.b/Example10_2b.sce
new file mode 100755
index 000000000..0af67cc0c
--- /dev/null
+++ b/506/CH10/EX10.2.b/Example10_2b.sce
@@ -0,0 +1,22 @@
+clear;
+clc;
+
+//Caption:amplifier using n channel FET
+
+//Given Data
+
+Vp=-2;//in V
+Idss=1.65;//in mA
+//it is desired to bias the circut at Id=0.8mA
+Ids=0.8;//in mA
+Vdd=24;//in V
+//Assumption: rd>Rd
+
+Vgs=Vp*(1-(Ids/Idss)^0.5);//in V
+
+gmo=-(2*Idss/Vp);
+disp('mA/V',gmo,'gmo=');
+gm=gmo*(1-(Vgs/Vp));
+disp('mA/V',gm,'gm=');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.2.c/Example10_2c.sce b/506/CH10/EX10.2.c/Example10_2c.sce
new file mode 100755
index 000000000..614ce9c00
--- /dev/null
+++ b/506/CH10/EX10.2.c/Example10_2c.sce
@@ -0,0 +1,23 @@
+clear;
+clc;
+
+//Caption:amplifier using n channel FET
+
+//Given Data
+
+Vp=-2;//in V
+Idss=1.65;//in mA
+//it is desired to bias the circut at Id=0.8mA
+Ids=0.8;//in mA
+Vdd=24;//in V
+//Assumption: rd>Rd
+
+Vgs=Vp*(1-(Ids/Idss)^0.5);//in V
+
+gmo=-(2*Idss/Vp);
+gm=gmo*(1-(Vgs/Vp));
+
+Rs=-(Vgs/Ids);//in ohm
+disp('K',Rs,'Rs=');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.2.d/Example10_2d.sce b/506/CH10/EX10.2.d/Example10_2d.sce
new file mode 100755
index 000000000..ecf781d47
--- /dev/null
+++ b/506/CH10/EX10.2.d/Example10_2d.sce
@@ -0,0 +1,27 @@
+clear;
+clc;
+
+//Caption:amplifier using n channel FET
+
+//Given Data
+
+Vp=-2;//in V
+Idss=1.65;//in mA
+//it is desired to bias the circut at Id=0.8mA
+Ids=0.8;//in mA
+Vdd=24;//in V
+//Assumption: rd>Rd
+
+Vgs=Vp*(1-(Ids/Idss)^0.5);//in V
+
+gmo=-(2*Idss/Vp);
+gm=gmo*(1-(Vgs/Vp));
+
+Rs=-(Vgs/Ids);//in ohm
+
+disp('20dB corresponds to voltage gain of i0');
+Av=10;
+Rd=Av/gm;//in ohm
+disp('ohm',Rd,'Rd=');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.3.a/Example10_3a.sce b/506/CH10/EX10.3.a/Example10_3a.sce
new file mode 100755
index 000000000..b36cb4781
--- /dev/null
+++ b/506/CH10/EX10.3.a/Example10_3a.sce
@@ -0,0 +1,26 @@
+clear;
+clc;
+
+//Caption: To find the parameters of a FET 2N3684
+
+//Given Values
+Vpmin=-2;//in V
+Vpmax=-5;//in V
+Idssmin=1.6;//in mA
+Idssmax=7.05;//in mA
+Idmin=0.8;//in mA
+Ia=Idmin;
+Idmax=1.2;//in mA
+Ib=Idmax;
+Vdd=24;//in V
+Vgs1=0;//in V
+Id1=0.9;//in mA
+Vgs2=-4;//in V
+Id2=1.1;//in mA
+//Slope determines Rs
+Rs=(Vgs1-Vgs2)/(Id2-Id1);
+disp('ohm',Rs,'Rs=');
+Vgg=Id1*Rs;
+disp('V',Vgg,'Vgg=');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.3.b/Example10_3b.sce b/506/CH10/EX10.3.b/Example10_3b.sce
new file mode 100755
index 000000000..274ef8d7c
--- /dev/null
+++ b/506/CH10/EX10.3.b/Example10_3b.sce
@@ -0,0 +1,14 @@
+clear;
+clc;
+
+//Caption:To find the range of possible values of Id in FET 2N3684 from the graph
+
+//In the figure given The line of Rs=3.3K cuts Vp = -2V at Id = 0.4 mA
+Idmin = 0.4;//in mA
+disp('mA',Idmin,'Idmin=');
+
+//In the figure given The line of Rs=3.3K cuts Vp = -5V at Id = 1.2 mA
+Idmax = 1.2;//in mA
+disp('mA',Idmax,'Idmax=');
+
+//end
+\ No newline at end of file
diff --git a/506/CH10/EX10.4/Example10_4.sce b/506/CH10/EX10.4/Example10_4.sce
new file mode 100755
index 000000000..11698cf04
--- /dev/null
+++ b/506/CH10/EX10.4/Example10_4.sce
@@ -0,0 +1,50 @@
+clear;
+clc;
+
+//Caption:Voltage Gain of MOSFET as a single stage and then as first transistor
+
+//Given Data
+Rd=100;//in K
+f=20000;//frequency in Hertz
+//MOSFET parameters
+gm=1.6;//in mA/V
+rd=44;//in k
+Cgs=3*(10^-12);//in F
+Cds=1*(10^-12);//in F
+Cgd=2.8*(10^-12);//in F
+m=gm*rd;//mew
+
+//Required Formulae
+Ygs=2*%pi*f*Cgs*%i;//in mho
+Yds=2*%pi*f*Cds*%i;//in mho
+Ygd=2*%pi*f*Cgd*%i;//in mho
+gd=1/rd;//in mho
+Yd=1/Rd;//in mho
+gm=1.6*(10^-3);//in mho
+disp('Gain of one stage amplifier');
+Av=(-gm+Ygd)/(gd+Yd+Yds+Ygd);//Voltage Gain
+disp(Av,'Av=');
+
+disp('Gain after nelecting the interelectrode capacitance');
+Av=-(m*Rd)/(Rd+rd);//Voltage Gain
+disp(Av,'Av=');
+
+//Let k= gm*Rd'
+k=-Av;
+Ci = (Cgs*(10^12)) +((1+k)*Cgd*(10^12));
+disp('Value of Input Impedence Capacitance');
+disp('pF',Ci,'Ci=');
+
+//Now considering a two stage amplifier consisting of an FET operating
+//New input Impedence taking into account various factors for present codition
+Ci=200*(10^-12);
+disp('Now considering a two stage amplifier consisting of an FET operating');
+Yl=(0.001/Rd)+(2*%pi*f*Ci*%i);
+disp(Yl,'Load Admittance =');
+
+gd=gd*0.001;
+disp('Gain');
+Av=-(gm)/(gd+Yl);//Voltage Gain
+disp(Av,'Av=');
+
+//end
+\ No newline at end of file