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diff --git a/479/CH4/EX4.9/Example_4_9.sce b/479/CH4/EX4.9/Example_4_9.sce new file mode 100755 index 000000000..9f32b8e39 --- /dev/null +++ b/479/CH4/EX4.9/Example_4_9.sce @@ -0,0 +1,29 @@ +//Chemical Engineering Thermodynamics
+//Chapter 4
+//Second Law of Thermodynamics
+
+//Example 4.9
+clear;
+clc;
+
+//Given
+m = 1;//mass of liquid water in Kg
+T1 = 1350;//initial temperature in deg celsius
+T2 = 400;//final temperature in deg celsius
+Cp = 1;//Specific heat of water in Kcal/Kg K
+Cpg = 0.2;//Specific heat of combustion gases in Kcal/Kg K
+Hv = 468.35;//Heat of vapourisation at 14 Kgf/cm^2 and 194.16 deg celsius in Kcak/Kg
+To = 298;//Surronding temperature
+Tb = 194.16+273;//Boiling point of liquid water
+
+//To Calculate the maximum work obtained and the entropy change
+//(i)Calculation of maximum work
+//Q = del_H = m*Cp*(T2-T1); gas can be assumed to cool at constant pressure
+//From equation 4.14 (page no 110)
+del_B = -((m*Cpg*(T2-T1))-(To*m*Cp*log((T2+273)/(T1+273))));
+mprintf('(i)The maximum work that can be obtained is %f Kcal/Kg of gas',del_B);
+
+//(ii)To Calculate the change in entropy
+del_S =(m*Cp*log(Tb/To))+((m*Hv)/Tb);
+mprintf('\n(ii)The entropy change per Kg of water is %f',del_S);
+//end
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