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+//Chemical Engineering Thermodynamics
+//Chapter 3
+//First Law of Thermodynamics
+
+//Example 3.9
+clear;
+clc;
+
+//To calculate the mass of steam required
+//Given
+m2 = 100;//mass of water to be heated
+//From diagram, 
+//m3 = m1+m2;..(a)
+//Hs = H1;..(b) since throttling is a constant enthalpy process
+//m3*H3-(m1*H1+m2*H2)=0;..(c) since delH=0
+
+//From steam tables, 
+Hs = 681.7//enthalpy of steam at 200 deg cel bleeded at the rate of 5Kgf/(cm^2) in Kcal/Kg
+H2 = 5.03;//enthalpy of liquid water at 5 deg cel
+H3 = 64.98;//enthalpy of liquid water at 65 deg cel
+//from equn (a),(b)&(c);(page no 80)
+m1 = ((H3-H2)/(Hs-H3))*m2;//mass of steam required in Kg  (page no 80)
+mprintf('The mass of steam required to heat 100 Kg of water is %f Kg',m1);
+//end 
+\ No newline at end of file